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2 years ago

Which is not a correct way to measure wavelength?

Physics

2 answers:

Monica [59]2 years ago

7 0

from rarefaction to rarefaction for a longitudinal wave

Simora [160]2 years ago

6 0

Rarefaction is the correct way

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Is the answer for h correct

goldfiish [28.3K]

Answer:

yess

Explanation:

good job kgkgjgkvvjcjc

3 0

3 years ago

How much ice (at 0Â°C) must be added to 1.90 kg of water at 79 Â°C so as to end up with all liquid at 8 Â°C? (ci = 2000 J/(kg.Â°

muminat

m = mass of the ice added = ?

M = mass of water = 1.90 kg

$c_{w}$ = specific heat of the water = 4186 J/(kg ⁰C)

$c_{i}$ = specific heat of the ice = 2000 J/(kg ⁰C)

$L_{f}$ = latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg

$T_{ii}$ = initial temperature of ice = 0 ⁰C

$T_{wi}$ = initial temperature of water = 79 ⁰C

T = final equilibrium temperature = 8 ⁰C

using conservation of heat

Heat gained by ice = Heat lost by water

m $c_{w}$ (T - $T_{ii}$ ) + m $L_{f}$ = M $c_{w}$ ( $T_{wi}$ - T)

inserting the values

m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)

m = 1.53 kg

4 0

3 years ago

Very lost please help.

V125BC [204]

A) The acceleration is due to gravity at any given point if you look at it vertically, so $-10 m/s^2$ .

b) $sin(25) = V_y/V$ , so $V_y = V*sin(25)$ . We use $V = V_0 + a t$ and then the final speed must be 0 because it stops at the highest point. So $0 = V_y - 10t$ . Solve for $t$ and you get $t = 32sin(25)/10 = 16sin(25)/5$

c) $Y = Y_0 + V_0t + (1/2)at^2$ , and then we plug the values: $Y_m_a_x = 32sin(25)*t - (1/2)*10*t^2$ and we already have the time from "b)", so $Y_m_a_x = [(32sin(25))*(32sin(25)/10)] - 5(32sin(25)/10)^2$ ; then we just rearrange it $Y_m_a_x = 10[(32sin(25))^2/100] - 5 [(32sin(25))^2/100]$ and finally $Y_m_a_x = 5[(32sin(25))^2/100] = (32sin(25))^2/20$

6 0

2 years ago

The height a ball bounces is less than the height of the previous bounce due to friction. The heights of the bounces form a geom

AlladinOne [14]

Answer:

Explanation:

Let the first height be h . second height .75h

third height .75h . fourth height .75²h

fifth height .75²h , sixthth height .75³ and so on

Total distance consists of two geometric series as follows

1 ) first series

h + .75h + .75²h + .75³h......

2 ) second series

.75h +.75²h +.75³h + .75⁴h .......

Sum of first series :

first term a = h , commom ratio r = .75

sum = a / (1 - r )

= h / 1 - .75

= h / .25

sum of second series :--

first term a = .75 h , commom ratio r = .75

sum = a / (1 - r )

= .75h / 1 - .75

= .75h / .25

Total of both the series

= 4h + 3h

= 7h .

h = 1 m

Total distance = 7 m

6 0

3 years ago

(a) Determine the specific volume of nitrogen gas at 8.5 MPa and 139 K based on the generalized compressibility chart (Fig. A-15

Vikentia [17]

Answer:v=0.0485m^3/kg

Explanation:

PV=MRT

PV/M=RT

Pv=RT

P=8.5mpa= 850Kpa

T= 139K

v= RT/P

0.2968*139/850

v=0.0485m3/kg

Error

0.0485-0.002002/0.0485*100%

95%

4 0

2 years ago