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Serggg [28]
4 years ago
5

there are two slides at the park between which you are deciding. Both start at the height of 6 meter. One is short and Steve whi

le the other is long and shallow. If both sides are frictionless, which one should you choose if you want to be moving as fast as possible at the bottom? A. short and steep. B. long and shallow. C. it doesn't matter.
Physics
1 answer:
kumpel [21]4 years ago
6 0

It doesn't matter.  If the slides are truly frictionless, then
your kinetic energy at the bottom will be equal to the
potential energy you had at the top, no matter what kind
of route you took getting down.
___________________________

The only way I can think of that it would make a difference
would be if the shallow slide were REALLY REALLY long,
and you didn't have anything to eat all the way down. 
Then you might lose some weight while you're on the slide,
and your mass might be less at the bottom than it was at the
top.  Then, in order to have the same kinetic energy at the
bottom, you'd need to be going a little bit faster.

But if it takes less than, say, two or three days, to go down the
long, shallow slide, then this effect would probably be too small
to make any difference.

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A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular
Fynjy0 [20]

Answer:

Bank angle = 35.34o

Explanation:

Since the road is frictionless,

Tan (bank angle) = V^2/r*g

Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2

Tan ( bank angle) = 40^2/(230*9.81)

Tan (bank angle) = 0.7091

Bank angle = tan inverse (0.7091)

Bank angle = 35.34o

3 0
3 years ago
A neutral atom possesses an atomic number of 13 and an atomic mass of 27. Three electrons are lost. From what region of the atom
slega [8]
The atomic number of the atom is 13. This means that its electronic configuration is (2 8 3) or in other words:
1<span>s2, </span>2<span>s2, </span>2<span>p6, </span>3<span>s2, </span>3<span>p<span>1

If three electrons are lost, then these electrons are removed from the outermost level.
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8 0
3 years ago
Does the image above correctly illustrate how the coriolis effect impacts global winds?
Sedbober [7]
Yes the winds are moving in a straight line
6 0
3 years ago
These type of winds are located between 30 and 60 degrees latitude on the globe.
vaieri [72.5K]

<u>B</u> option is correct    .

7 0
4 years ago
At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. At the same inst
kifflom [539]

Answer:

66.85 m

Explanation:

We are given that

Acceleration ,a=2.7m/s^2

Speed of truck, v=9.5 m/s

We have to find the distance beyond which the traffic signal will the automobile overtake the truck.

Initial speed of automobile, u=0

We know that

s=ut+\frac{1}{2}at^2

Using the formula

s=0+\frac{1}{2}(27)t^2=\frac{27}{2}t^2

For constant speed

Acceleration, a=0

Again

s=vt+0=9.5t

9.5t=\frac{27}{2}t^2

t=\frac{9.5\times 2}{2.7}=7.037s

Substitute the value of t

x=9.5(7.037)=66.85m

Hence, the distance beyond which the traffic signal will the automobile overtake the truck=66.85 m

3 0
3 years ago
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