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Liula [17]
3 years ago
5

A remote-controlled car’s wheel accelerates at 22.2 rad/s2 . If the wheel begins with an angular speed of 11.0 rad/s, what is th

e wheel’s angular speed after exactly twelve full turns? Answer in units of rad/s.
Physics
1 answer:
wariber [46]3 years ago
4 0

The angular speed remained constant after twelve turns at 11 rad/s.

Explanation:

As per the Newtons equation of motion, the final velocity can be determined by using the below equation, provided ,the displacement and acceleration with initial velocity is given.

v^{2}= u^{2}+2as

Since, the present case follows circular motion, the displacement will be equal to angular displacement. And the velocity is equal to angular velocity.

As the car revolves complete twelve turns, then the displacement will be zero, since the final position is equal to the initial position.

So,

v^{2}= (11)^{2}+2*22.2*0\\\\v = 11 rad/s

Thus, the angular speed remained constant after twelve turns at 11 rad/s.

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Why would a landslide be more likely on a steep mountain than on a gently sloping hill?
Serjik [45]
Steep mountain, due to gravity.
4 0
3 years ago
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A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

T = tension

Put the value into the formula

v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}

v =519.61\ m/s

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
3 years ago
When you rub a plastic rod with fur, the plastic rod becomes negatively charged and the fur becomes positively charged. As a con
Yuri [45]

Answer: C. the rod gains mass and the fur loses mass.

Explanation:Atomic particles have mass. The electron has a mass that is approximately 1/1836 that of the proton and with exchange exchange of charge this is also factored in. The movement of effect described above is known as the triboelectic charging process—charging by friction—which results in a transfer of electrons between the two objects when they are rubbed together. Plastic having a much greater affinity for electrons than animal fur pulls electrons from the atoms of fur, leaving both objects with an imbalance of charge. The plastic rod would have an excess of electrons and the fur has a shortage of electrons. Having an excess of electrons, the plastic is charged negatively and has more mass. In the same vein, the shortage of electrons on the fur leaves it with a positive charge and consequently with lesser mass.

4 0
3 years ago
Hold a pencil in front of your eye at a position where its blunt end just blocks out the Moon.
Valentin [98]

Answer:

D = 3.55 \times 10^6 m

Explanation:

Light rays coming from moon is blocked by the pencil

so as per figure we know that angle subtended by pencil and angle subtended by moon must be same

so we have

Angle = \frac{Arc}{Radius}

so we have

\frac{D}{3.8 \times 10^8 m} = \frac{0.7 cm}{75 cm}

so we have

D = 3.55 \times 10^6 m

4 0
3 years ago
A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
3 years ago
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