A remote-controlled car’s wheel accelerates at 22.2 rad/s2 . If the wheel begins with an angular speed of 11.0 rad/s, what is th
1 answer:
The angular speed remained constant after twelve turns at 11 rad/s.
Explanation:
As per the Newtons equation of motion, the final velocity can be determined by using the below equation, provided ,the displacement and acceleration with initial velocity is given.
Since, the present case follows circular motion, the displacement will be equal to angular displacement. And the velocity is equal to angular velocity.
As the car revolves complete twelve turns, then the displacement will be zero, since the final position is equal to the initial position.
So,
Thus, the angular speed remained constant after twelve turns at 11 rad/s.
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Answer:
Explanation:
The resistance increases linearly with the temperature - so we can write:
where
is the change in resistance
k is the coefficient of proportionality
is the variation of temperature
In the first part of the problem, we have
So the coefficient of proportionality is
When the resistance is , the change in resistance with respect to the resistance at zero degrees is
So we can find the change in temperature as:
So the new temperature is
Answer:
The work done required on the coin during the displacement is 21.75 w.
Explanation:
Given that,
A coin slides over a friction-less plane i.e friction force = 0.
The co-ordinate of the given point is (1.40 m, 7.20 m).
The position vector of the given point is represented by .
The displacement of the coin is
The force has magnitude 4.50 N and its makes an angle 128° with positive x axis.
Then x component of the force = 4.50 cos128°
The y component of the force = 4.50 sin128°
Then the position vector of the force is
We know that,
work done is a scalar product of force and displacement.
=(-2.77×1.40+ 3.56×7.20) w
=21.75 w
The work done required on the coin during the displacement is 21.75 w.