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mestny [16]
2 years ago
5

The international space station travels at a distance of about 250 miles above Earth’s surface and at a speed of 17,500 miles pe

r hour. Even though space dust and debris can be tiny, 1 centimeter or less in size with a mass of 10 grams or less, there is always fear that the space station will sustain damage from a collision with a small piece of space debris.
Why should scientists be concerned about a collision with such a tiny object? Use evidence and scientific reasoning to explain your answer.
Physics
1 answer:
Arisa [49]2 years ago
3 0

Answer:

In this case we are dealing with the pythagorean theorm involving right angled triangles. This theorm states that a^2 + b^2 = c^2 which means the square of the hypotenuse (side c, opposite the right angle) is equal to the square of the remaining two sides.

In this case we will say that a = 3963 miles which is the radius of the earth. c is equal to the radius of the earth plus the additional altitude of the space station which is 250 miles; therefore, c = 4213 miles. We must now solve for the value b which is equal to how far an astronaut can see to the horizon.

(3963)^2 + b^2 = (4213)^2

b^2 = 2,044,000

b = 1430 miles.

The astronaut can see 1430 miles to the horizon.

Explanation:

:D hopes this Helps

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The stopcock connecting a 2.14 L bulb containing oxygen gas at a pressure of 8.19 atm, and a 9.84 L bulb containing krypton gas
marshall27 [118]

Answer : The final pressure of the system in atm is, 3.64 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1+P_2V_2=P_fV_f

where,

P_1 = first pressure = 8.19 atm

P_2 = second pressure = 2.65 atm

V_1 = first volume = 2.14 L

V_2 = second volume = 9.84 L

P_f = final pressure = ?

V_f = final volume = 2.14 L  + 9.84 L = 11.98 L

Now put all the given values in the above equation, we get:

8.19atm\times 2.14L+2.65atm\times 9.84L=P_f\times 11.98L

P_f=3.64atm

Therefore, the final pressure of the system in atm is, 3.64 atm

4 0
3 years ago
5. You require a high-current battery to start a large tractor. While shopping
Yakvenalex [24]

Answer:

I have no clue sorry I wish I could help

3 0
3 years ago
The Jurassic Park ride at Universal Studios theme park drops 25.6 m straight down essentially from rest. Find the time for the d
ankoles [38]

Answer:

V=22.4m/s;T=2.29s

Explanation:

We will use two formulas in order to solve this problem. To determine the velocity at the bottom we can use potential and kinetic energy to solve for the velocity and use the uniformly accelerated displacement formula:

mgh=\frac{1}{2}mv^{2}\\\\X= V_{0}t-\frac{gt^{2}}{2}

Solving for velocity using equation 1:

mgh=\frac{1}{2}mv^{2} \\\\gh=\frac{v^{2}}{2}\\\\\sqrt{2gh}=v\\\\v=\sqrt{2*9.8\frac{m}{s^2}*25.6m}=22.4\frac{m}{s}

Solving for time in equation 2:

-25.6m = 0\frac{m}{s}t-\frac{9.8\frac{m}{s^{2}}t^{2}}{2}\\\\-51.2m=-9.8\frac{m}{s^{2}}t^{2}\\\\t=\sqrt{\frac{51.2m}{9.8\frac{m}{s^{2}}}}=2.29s

7 0
3 years ago
A container with a mass of 5 kg is lifted to a height of 8 m
Ne4ueva [31]

It takes 392 joules of work to lift it.

It has 392 joules of gravitational potential energy up there.

3 0
3 years ago
Make the following prefix conversions.<br> 0.001s =ms
Free_Kalibri [48]

Answer:

To convert a millisecond measurement to a second measurement, divide the time by the conversion ratio. The time in seconds is equal to the milliseconds divided by 1,000.

Explanation:

hope it helps

4 0
2 years ago
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