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nalin [4]
4 years ago
5

A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocit

y of 153 meters/second. what distance has the spaceship covered after 12.0 seconds?
Physics
1 answer:
Naddika [18.5K]4 years ago
8 0
The ship's average speed during the 12 seconds is

                         (1/2) (58 + 153)

                     =  (1/2) (211 m/s)

                     =        105.5 m/s .

Traveling for 12 seconds at an average speed of  105.5 m/s ,
the ship covers

               (12 sec) x (105.5 m/s)

           =        1,266 meters  during the acceleration
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The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.

<u>Explanation:</u>

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