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anyanavicka [17]
3 years ago
10

Which of the following would demonstrate an attraction between magnetic poles?

Physics
2 answers:
Korolek [52]3 years ago
8 0

Answer: The correct answer is C: North pole to a south pole.

Explanation: Opposite poles attract each other while alike poles repel one another.

hope this helps (:

vredina [299]3 years ago
5 0
"C. north pole to a south pole" would demonstrate an attraction between magnetic poles, since in the field of magnetics, opposites attract and similar forces repel one another. 
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What is the apparent weight of this same object at Neptune's equator? (Note that Neptune's "surface" is gaseous, not solid, so i
guajiro [1.7K]

Answer:

Explanation:

Acceleration of gravity on the surface of

Neptune is given

g' = G M/R^2,

where M is the planet's mass.

M g' will be the apparent weight registed at the poles.

G is the universal constant of gravity

The "apparent weight" at the equator will be

reduced from M g' by the centripetal force M

R w^2, where w is the rotational angular

velocity in radians/s), which you can deduce

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5 0
3 years ago
Read 2 more answers
Which is a characteristic of atoms?
andriy [413]

Answer: 2

Explanation: bro this is literally basic knowledge

8 0
2 years ago
Why don't the two forces in Newton's third law cancel each other? They act in the same direction. They are different kinds of fo
pogonyaev

Answer:They act on different bodies

Explanation:

Newton's third law of motion states that for every action there is equal and opposite reaction i.e. action and reaction. Though action and reaction are equal they act in different bodies that is why they do not cancel out each other.

For example, a block of mass m placed over the table exerts a force of mg to the table while the table applies a Normal reaction of equal magnitude as of mg to the block of mass m.

5 0
3 years ago
600 kg elephant runs at 5 m/s and jumpts onto a 100kg cart. If the coefficient of friction is .04 how far will the cart travel o
Minchanka [31]

Answer:

Eleven seconds.

Explanation:

Two keys are needed to solve this problem. First, the conservation of momentum: allowing you to calculate the cart's speed after the elephant jumped onto it. It holds that:

m_ev_e+m_c\cdot0=(m_e+m_c)v_0\implies \\v_0=\frac{m_ev_e}{m_e+m_c}=\frac{600kg\cdot 5\frac{m}{s}}{700kg}=4.29\frac{m}{s}

So, once loaded with an elephant, the cart was moving with a speed of 4.29m/s.

The second key is the kinematic equation for accelerated motion. There is one force acting on the cart, namely friction. The friction acts in the opposite direction to the horizontal direction of the velocity v0, its magnitude and the corresponding deceleration are:

F_r = 0.04\cdot (m_e+m_c)g\implies a_r = 0.04\cdot g= 0.04 \cdot 9.8 \frac{m}{s^2}=0.39\frac{m}{s^2}

The kinematic equation describing the decelerated motion is:

v = -a_r t+v_0\\0 = -a_rt+v_0\implies \\t = \frac{v_0}{a_r}=\frac{4.29\frac{m}{s}}{0.39\frac{m}{s^2}}=11s

It takes 11 seconds for the comical elephant-cart system to come to a halt.

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4 years ago
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3 years ago
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