The royals softball team played 75 games and won 55 of them. What percent of the games did they lose (round to the nearest hundr
2 answers:
If they won 55 of the games, that means they lost the rest of the 75. So,
75 - 55 = 20 games lost. To find the percentage of 20 out of 75, you set up a proportion:
where x = the percentage of games lost. Cross multiply and divide to isolate the x:
Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.
75 - 55 = 20 games lost. To find the percentage of 20 out of 75, you set up a proportion:
where x = the percentage of games lost. Cross multiply and divide to isolate the x:
Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.
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Answer:
150 degrees
Step-by-step explanation:
Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.
So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length . The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.
Let's find the complementary angle.
So the opposite side of the complementary angle is 5.
The adjacent side of the complementary angle is .
So 90-30=60.
The answer therefore 60+90=150.
<h2>Answer:</h2>
y = x + 3
As shown in the graph, the line is a straight line. Therefore, the general equation of a straight line can be employed to derive the equation of the line.
The general equation of a straight line is given by:
y = mx + c <em>or </em>-------------(i)
y - y₁ = m(x - x₁) -----------------(ii)
Where;
y₁ is the value of a point on the y-axis
x₁ is the value of the same point on the x-axis
m is the slope of the line
c is the y-intercept of the line.
Equation (i) is the slope-intercept form of a line
Steps:
(i) Pick any two points (x₁, y₁) and (x₂, y₂) on the line.
In this case, let;
(x₁, y₁) = (0, 3)
(x₂, y₂) = (4, -2)
(ii) With the chosen points, calculate the slope <em>m</em> given by;
m =
m =
m =
(iii) Substitute the first point (x₁, y₁) = (0, 3) and m = into equation (ii) as follows;
y - 3 = (x - 0)
(iv) Solve for y from (iii)
y - 3 = x
y = x + 3 [This is the slope intercept form of the line]
Where the slope is and the intercept is 3