What does 7^x=21 in a logarithmic equation

Mathematics

1 answer:

Leviafan [203]3 years ago

8 0

Loga x=n ⇔ a^n=x
log₇ 21=x

x=log ₇ 21
x=ln 21 / ln7=1.564575034...

Answer: x=log₇ 21

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