34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.
Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. 
Here μ to μ + σ = 
Hence 34% of the scores lie between 433 and 523.
Let the two numbers be x and y.
x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________
2x = 98
x = 98/2
x = 49
From x + y = 86
49 + y = 86
y = 86 - 49
y = 37
The numbers are 49 and 37.
Answer:
the answer of ur eternity is
Step-by-step explanation:
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Answer to your question is 13.24
The percentage of the average yearly wage is 7.53%.
<h3>What are percentages?</h3>
Percentage can be described as a fraction of an amount that is usually expressed as a number out of hundred.
<h3>What is the percentage of the average yearly wage?</h3>
Percent = (amount spent on family holiday / total yearly wage) x 100
(1644 / 21842) x 100 = 7.53%
To learn more about percentages, please check: brainly.com/question/25764815
