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STALIN [3.7K]
3 years ago
5

Find the inequalitie for d thank youuu -7d+8>29

Mathematics
1 answer:
shutvik [7]3 years ago
3 0

Answer:

d<3

Step-by-step explanation:

-7d+8>29

First lets remove the inequality  for know

-7d+8=29

then remember to re add the inequality to the equation

-7d>21

since you divide by negative you switch

d<3

that is your answer

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Midpoint Between Two Given Points
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
What two facts can you double to find 8x4? explain
almond37 [142]
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6 0
3 years ago
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach
nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that \mu = 130, \sigma = 30

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 130}{30}

X - 130 = 0.675*30

X = 150.25

A score of 150.25 is necessary to reach the 75th percentile.

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3 years ago
Find the quotient 400÷8
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The quotient is 50 :)

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3 years ago
Read 2 more answers
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