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Olenka [21]
3 years ago
14

Evaluate the expression, using the given value of the variable.

Mathematics
2 answers:
natka813 [3]3 years ago
3 0
-10 is the answer to the question above.
Natali [406]3 years ago
3 0

Answer:

-10

Step-by-step explanation:

2-6x+2x

2-(6*3)+(2*3)

2-18+6

-16+6

-10

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5) Rolanda scored 20, 15and 16 on hefirst three mathquizzes. Jetta scored 16, 19and17 on her quizzes Usingthe mean to compare, w
Wittaler [7]
To find mean/average it's fairly simple!! :)

The first thing you should do is add up the first numbers -
* 20 + 15 + 16 = 51 :)
* 16 + 19 + 17 = 52

Now divide each of the scores by the amount of numbers there is -
* 20 (1) 15 (2) 16 (3)
* 16 (1) 19 (2) 17 (3)

51 ÷ 3 = 17 (Rolanda's Average Score)
- Which # is bigger?
52 ÷ 3 = 17.3 (Jetta's Average Score)
8 0
3 years ago
Read 2 more answers
Please help me with this
swat32

Answer:

The answer is 156.25π or about 490.625

Step-by-step explanation:

To find the area of a circle, you use the formula πr² (pi times radius times radius.) The radius is 12.5, so you plug it in to the equation. Once you plug the radius into the equation, you get π times 12.5 times 12.5. This simplifies to 156.25 times pi. If you want to use 3.14 as pi, the final answer is about 490.625. I hope this helps and that you have an fantastic day!!! Hope you stay safe!!!

6 0
3 years ago
2 1/4 x 3 2/5<br> show all your work
monitta

Answer:

153/20

Step-by-step explanation:

I assume you're asking

2 \frac{1}{4}  \times 3 \frac{2}{5}

So

\frac{9}{4}  \times  \frac{17}{5}

=

\frac{153}{20}

5 0
3 years ago
10. The sum of three consecutive integers is 45. What are the three integers?
spayn [35]

Answer:

<h3>            14, 15, 16</h3>

Step-by-step explanation:

The consecutive integers iincrease by 1. So the middle integer of an odd number of consecutive integers is their mean. Three is an odd number of integers.

45:3 = 15   ← middle number

15 - 1 = 14   ← the smallest number

15 + 1 = 16  ← the largest number

8 0
3 years ago
A popular resort hotel has 300 rooms and is usually fully booked. About 7% of the time a reservation is canceled before the 6:00
kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that n = 300

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied.  So we use p = 0.93

Approximating the binomial to the normal.

E(X) = np = 300*0.93 = 279

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.93*0.07} = 4.42

The probability that at least 285 rooms will be occupied is 1 subtracted by the pvalue of Z when X = 285. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{285- 279}{4.42}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131.

So there is a 1-0.9131 = 0.0869 = 8.69% probability that at least 285 rooms will be occupied.

8 0
3 years ago
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