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maxonik [38]
3 years ago
12

Painting. Quentin can paint the turret on a Queen Anne house in 40 hr. It takes Austin 50 hr to paint the same turret. How long

would it take them, working together, to paint the turret?
Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

The answer to your question is 22.2 hours

Step-by-step explanation:

Data

Quentin      40 hr to paint a turret

Austin         50 hr to paint a turret

Use proportions to solve this problem

Quentin        1 turret ---------------- 40 hr    Austin   1 turret --------------- 50 hr

                    x            ----------------   1 hr                   x         ---------------- 1 hr

                    x = 0.025 turret                                  x = 0.02 turret

Then

- In 1 hour they paint              0.025 + 0.02 = 0.045 of the turret

- In 10 hours they paint     (10 x 0.025 + 10 x 0.02) = 0.25 + .2 = 0.45

- In 20 hours they paint    (20 x 0.025 + 20 x 0.02) = 0.5 + 0.4 = 0.9

- In 22 hours they paint    (22 x 0.025 + 22 x 0.02) = 0.55 + 0.44 = 0.99

- In 22.2 hours they paint (22.2 x 0.025 + 22.2 x 0.02) = 0.555 + .0.444 =

                                                                                                                     0.999

They paint the turret together in 22.2 hours  

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The ratio of the side lengths for a triangle is exactly 9:12:15. In another triangle, which is similar to the first, the shortes
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Step-by-step explanation:

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3 years ago
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Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 \neq 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 \neq 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 \neq 13

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3 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION
Murljashka [212]

Answer:

The value of DC is 66.34.

Step-by-step explanation:

The triangles ABC and DCA are right angled triangles.

The straight line AC is a bisector for angles C and A.

The measure of ∠C is 30°.

Then the measure of angles BCA and ACD will be 15° each.

The measure of angle DAB is 150°.

Then the measure of angles DAC and BAC will be 75° each.

Now consider the right angled triangle ABC.

The measure of side AC is:

AC^{2}=AB^{2}+BC^{2}\\AC=\sqrt{AB^{2}+BC^{2}}\\=\sqrt{4^{2}+(10\sqrt{3})^{2}}\\=\sqrt{316}

Consider the right angled triangle DCA.

The angle DAC measure 75°.

Using the trigonometric identities compute the value of Perpendicular DC as follows:

tan\ 75^{o}=\frac{DC}{\sqrt{316}}\\\\DC=3.732\times\sqrt{316}\\\\DC=66.34

Thus, the value of DC is 66.34.

7 0
3 years ago
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