solve each triangle. round each side length to the nearest tenth and angle measures to the nearest degree. a= 14, c= 20, B= 38 d
egrees.
2 answers:
A) the missing degree is 166
b) the missing degree is 142
c)the missing degree is 160
I do hope I helped you in a way! If I am incorrect I apologize.
Okay after scratching my head and some scrap paper :P I was really surprised to see that I don't remember ever running into this before...
Using the Law of Cosines we find the third side.
c=√(196+400-560cos38)≈12.4384 (we can round further for the final answer)
Now using the Law of Sines for the other angles.
sin38/12.4384=sinA/14=sinB/20
A=arcsin(14sin38/12.4384)≈43.8645°
BUT what I didn't realize before is that B was obtuse which means:
B=180-arcsin(20sin38/12.4384)≈98.135°
So solved for sides and angles (with rounding asked for)
(14, 44°), (12.4, 38°), and (20, 98°)
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