Answer:
6.5 seconds
Step-by-step explanation:
Ok so the equation you gave is -16T^2 + 676 in the comments which is what I'll be using for this problem. The problem is really just asking you to find the zeroes of the equation excluding any negative solutions since that doesn't really represent anything in this context since T is time.
So the first step is to set the equation equal to 0
.
Subtract 676 from both equations.
Divide both sides by -16
Take the square root of both sides
Ignore the negative and take only the positive solution, since in this context it doesn't make much sense. So after 6.5 seconds the height is 0, meaning it hits the ground after 6.5 seconds.
It would be A. because it intercepts the x-axis and y-axis at (0, 0) and D. because it looks like a u
Answer:
46.5
Step-by-step explanation:
Square roots and squaring are always nonlinear.
Answer: Non of the option.
Step-by-step explanation:
The given equation is
4x^3 - 6x^2 + 15x + 2 = 0
Let's test 1, if it's one of the root. I.e
If x = 1
4 - 6 + 15 + 2 = 15
Positive 1 is not a root to the equation
If x = - 1
-4 - 6 - 15 + 2 = - 23
Negative 1 is not a root
If x = 2
4x8 - 6×4 + 15×4 + 2
32 - 24 + 30 + 2 = 40
Positive 2 is not a root
If x = - 2
4×(-8) - 6×4 - 15×2 + 2
-32 - 24 - 30 + 2 = -84
Negative 2 is not a root
If x = 3
4×27 - 6×9 + 15×3 + 2
108 - 54 + 45 + 2 = 101
Since non of them tend to zero, non of the option is a root of the equation
