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Dvinal [7]
3 years ago
11

Pleaseeeee helppp!!!!!!!!!!!

Mathematics
1 answer:
Mrrafil [7]3 years ago
5 0
4^{2x}=7^{x-1}\\
16^x=7^x\cdot7^{-1}\\
\dfrac{16^x}{7^x}=\dfrac{1}{7}\\
\left(\dfrac{16}{7}\right)^x=\dfrac{1}{7}\\
x=\log_{\tfrac{16}{7}}\dfrac{1}{7}\approx-2.35389
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