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agasfer [191]
3 years ago
12

The longer base of an isosceles trapezoid measures 23 ft. The nonparallel sides measure 9 ft, and the base angles measure 80°. F

ind the length of a diagonal.

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:23 feet

Step-by-step explanation:

snow_lady [41]3 years ago
3 0
Check the picture.

Consider the triangle DAB, with |DA|=9 ft, |AB|=23 ft and m(DAB)=80°.

To find the length of the diagonal, |DB|, we use the cosine law:

|DB|^{2}= |DA|^{2} + |DA|^{2} -2|DA|*|AB|*cos(DAB)

=9^{2}+23^{2}-2*9*2*(0.173)=81+529-6.228=603.7

Thus, |DB|= \sqrt{603.7}=24.6 (ft)


Answer: 24.6 ft

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