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Mama L [17]
3 years ago
6

What is vertex of x^2+5x-3

Mathematics
1 answer:
Art [367]3 years ago
6 0

\text{The vertex of}\ ax^2+bx+c:\\\\(h,\ k),\ \text{where}\ h=\dfrac{-b}{2a};\ k=f(h)=\dfrac{-(-b^2-4ac)}{4a}

\text{We have:}\\f(x)=x^2+5x-3\\\\a=1,\ b=5,\ c=-3\\\\h=\dfrac{-5}{2\cdot1}=\dfrac{-5}{2}=-2.5\\\\k=f(-2.5)=(-2.5)^2+5(-2.5)-3=6.25-12.5-3=-9.25

\text{Answer: the vertex is in}\ (-2.5;\ -9.25)

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The question is the picture thanks for helping
Vedmedyk [2.9K]

Answer:

Answer is option b)

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

a \: walking \: path \: is \: represented \: by \:  \\ y =  - 4x - 6 \\ 4x + y + 6 = 0 \\ given \: that \\ a \: new \: path \: will \: be \: built \: perpendicular  \\ \: to \:  \: the \: walking \: path \\ the \: equation \: of \: the \: line \: perpendicular \: to \\ 4x + y + 6 = 0 \: is \\ x - 4y + k = 0 \\ since \: it \: passes \: through \: ( - 4,10) \\ substitute \: x \:  =  - 4\: and \: y = 10 \: in \: required \: equation \\  - 4 - 4(10) + k = 0 \\ k = 44 \\ then \: the \: equation \: is \\ x - 4y + 44 = 0 \\ adding \: 4y \: on \: both \: sides \\ x + 44 = 4y \\ dividing \: by \: 4 \: on \: both \: sides \\ y =  \frac{x}{4}  + 11 \\ y =  \frac{1}{4} x + 11 \\ so \: the \: answer \: is \: option \: b) \:   \frac{1}{4} x + 11

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

8 0
3 years ago
Read 2 more answers
100 Points!
tester [92]

Part A: x = -5/4, 3 || (-5/4, 0) (3, 0)

To find the x-intercepts, we need to know where y is equal to 0. So, we will set the function equal to 0 and solve for x.

4x^2 - 7x - 15 = 0

4 x 15 = 60 || -12 x 5 = 60 || -12 + 5 = -7

4x^2 - 12x + 5x - 15 = 0

4x(x - 3) + 5(x - 3) = 0

(4x + 5)(x - 3) = 0

4x + 5 = 0

x = -5/4

x - 3 = 0

x = 3

Part B: minimum, (7/8, -289/16)

The vertex of the graph will be a minimum. This is because the parabola is positive, meaning that it opens to the top.

To find the coordinates of the parabola, we start with the x-coordinate. The x-coordinate can be found using the equation -b/2a.

b = -7

a = 4

x = -(-7) / 2(4) = 7/8

Now that we know the x-value, we can plug it into the function and solve for the y-value.

y = 4(7/8)^2 - 7(7/8) - 15

y = 4(49/64) - 49/8 - 15

y = 196/64 - 392/64 - 960/64

y = -1156/64 = -289/16 = -18 1/16

Part C:

First, start by graphing the vertex. Then, use the x-intercepts and graph those. At this point we should have three points in a sort of triangle shape. If we did it right, each of the x-values will be an equal distance from the vertex. After we have those points graphed, it is time to draw in the parabola. Knowing that the parabola is positive, we draw in a U shape that passes through each of the three points and opens toward the top of the coordinate grid.

Hope this helps!

6 0
2 years ago
A line that passes through the point (4, 2) and has the slope of -3/2
mash [69]
The answer is: y = -3/2 x + 8

Graph:

To find the answer we use the formula;

y-y1 = M1 (x - x1)

y-2 = -3/2 (x-4)

When fully solved: the answer is:
y = -3/2 x + 8

8 0
3 years ago
How do yo find slope
Yuliya22 [10]
X2 minus x1/y2 minus y1 is how u find slope
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3 years ago
What is the simplified form of the expression?
Veronika [31]

Question 2 options:

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729x29

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4 years ago
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