Question

What is the total number of moles of solute in 250 milliliters of a 1.0 M solution of NaCl? 1. 1.0 mole 2. 0.25 mole 3. 0.50 mole 4. 42 moles

Answer 1

Hope this helps you with your answer.

NaCl --> Na+ + Cl-

c= n/V

n= c*V= 1.0 mol dm^-3 * 0,250 dm^3= 0,25 mol (mol dm^-3= M; mL= cm^3)

but you need to multiply that with 2 be cause you have 0,25 moles of Na+ and 0,25 moles of Cl- so the answer is 3) 0,50 moles

;)

ps you need to take into account both species be cause from 1 mole of NaCl you get 1 mole of Cl- and one mole of Na+ and when you add that up you get 2 moles

Answer 2

Answer:

0.25moles

Explanation:

number of moles = concentration × volume

number of moles = ?moles

concentration of solute = 1.0M = 1.0mol/L

volume = 250mL = 250 × 10⁻³L = 0.25L

n= 1 × 0.25 = 0.25moles