The example of a chemical combination that can also be said to be a synthesis reaction is;
<h3>What is a synthesis reaction?</h3>
We know that the meaning of the synthesis reaction is quite central as we attempt to answer the question that is lying right before us here. If we are talking about the synthesis reaction then our mind must have to go to the kind of reaction in which there is the combination of two or more so as to produce a single compound.
As we are talking about the synthesis reaction, we would have to look at the reaction that would give rise to a single product as it has been written. Let us also recall that we have been told that the reaction is a oxidation-reduction reaction thus there is a change in oxidation number in the process of the reaction as shown.
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Mass spectrum of Dodecane will give following information.
1 ) Molecular Peak or Parent Peak:
The Parent peak will appear at m/z = 170. The intensity of this peak will be very weak.
2) Fragments:
Usually the fragments of such long chain alkanes appear with spacing of 14 amu, Hence, the peaks in dodecane will be as follow,
170 - 156 - 142 - 128 - 114 - 100 - 86 - 72 - 58 - 44 - 30 - 16
3) Base Peak:
Most probably the Base peak will appear at m/z = 57. This peak is due to the formation of tertiary butyl cation as the intensity mainly depends upon the stability of cation. So this cation might form due to rearrangment giving the intensity of 100%.
Answer:
Brass
Explanation:
Brass is an alloy of copper and zinc, in proportions which can be varied to achieve varying mechanical and electrical properties.
First, we write the balanced equation for this reaction:
2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂
From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:
Moles = volume (in L) * molarity
We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:
M₁V₁ = 2M₂V₂
V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L
The volume required is 173.6 mL
4 protons the number of proton has the same number of electron [which is the same as atomic number]