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IgorC [24]
3 years ago
13

An atom of gold has a mass of 3.271 x 10-22g. How many atoms of gold are in 5.00g of gold?

Chemistry
1 answer:
rosijanka [135]3 years ago
3 0
To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation  \frac{mass of gold}{mass of gold atom}. 

Let x be the number of gold atoms. Plug in the values to a calculator.

x = \frac{5.00g}{3.271 x 10-22g}
Both have the same units so the unit gram(g) can be cancelled. 
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold
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Complete and balance each of the following equations for gas evolution reactions HCl(aq)+ZnS(s)>
DENIUS [597]

2HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)

<h3>Further explanation  </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:  

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.  
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product  
  • 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)

1. give equation

aHCl(aq) + bZnS(s) ⇒ ZnCl₂(aq) + cH₂S(g)

2. make an equation

H, left=a, right=2c⇒a=2c(eq 1)

Cl, left=a, right=2⇒a=2⇒c=1(from eq 1)

Zn, left=b, right=1⇒b=1

So the equation :

2HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)

4 0
3 years ago
Calcium carbonate is often used as an antacid. Your stomach acid is composed of HCl at a pH of 1.5. If you ate toooo much Turkey
stiks02 [169]

<u>Answer:</u> 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

pH=-\log [H^+]      .....(1)

Given value of pH = 1.5

Putting values in equation 1:

1.5=-\log[H^+]

[H^+]=10^{(-1.5)}=0.0316M

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}       .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol

The chemical equation for the reaction of HCl and calcium carbonate follows:

2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, 4.74\times 10^{-4}mol of HCl will react with = \frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of calcium carbonate = 2.37\times 10^{-4}mol

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

7 0
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melomori [17]
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