Question

Y''-4y=cosx find general solution.

Answer 1

Answer:

Step-by-step explanation:

$y''-4y=cosx$

The auxialary equation and solutions are as follows:

$m^2-4=0\\m=2,-2$

General solution is

$y=Ae^{2x} +Be^{-2x}$

Right side =cosx

Particular Integral

= $\frac{cosx}{-1-4} =\frac{-cosx}{5}$

Hence full solution is