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love history [14]
3 years ago
5

Y''-4y=cosx find general solution.

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

Step-by-step explanation:

y''-4y=cosx

The auxialary equation and solutions are as follows:

m^2-4=0\\m=2,-2

General solution is

y=Ae^{2x} +Be^{-2x}

Right side =cosx

Particular Integral

= \frac{cosx}{-1-4} =\frac{-cosx}{5}

Hence full solution is

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