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Rama09 [41]
2 years ago
9

Need help with it I don’t know how to do it

Mathematics
1 answer:
mario62 [17]2 years ago
8 0
Dkdnksskmsmsmsmsmsmsmsmsms D)
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What is the value of c in the equation 12 c minus 53 = 91?
dmitriy555 [2]

Answer:

c=12

Step-by-step explanation:

12c - 53= 91

12c=144

c=12

5 0
3 years ago
Please help, my teacher never went over this with us.
laiz [17]

Answer:

F ) √ 9/64

Step-by-step explanation:

√ 9/64 simplifies into 3/8, which is a rational number

6 0
3 years ago
The relationship between the slopes of two lines that are parallel is _____________.
a_sh-v [17]
They are the same slope

they are negative inversees (they multily to get -1)

2

-1/2

use the square viewer (on TI)





The relationship between the slopes of two lines that are parallel is they are the same. The relationship between the slopes of two lines that are perpendicular is they are negative inverses of each other (they multiply to -1).
A line that is parallel to a line whose slope is 2 has slope 2.
A line that is perpendicular to a line whose slope is 2 has slope -1/2.

What must be done to make the graphs of two perpendicular lines appear to intersect at right angles when they are graphed using a graphing utility?

8 0
3 years ago
Read 2 more answers
The line plots show the results of a survey of 12 boys and 12 girls about how many hours they spent reading for pleasure the pre
lana66690 [7]

Answer:

The range for boys is 0-12 and the mean is 5.1

The range for girls is 2-8 and the mean is 5.3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find X and y<br><br> 12, 16
zavuch27 [327]

Answer:

  • x = 6√2
  • y = 6√6

Step-by-step explanation:

The triangles are all similar, so corresponding sides are proportional.

__

<h3>x</h3>

  long side/short side = x/6 = 12/x

  x² = 72 . . . . . . . multiply by 6x

  x = 6√2 . . . . . . take the square root

__

<h3>y</h3>

  hypotenuse/long side = y/12 = (12+6)/y

  y² = 216 . . . . . multiply by 12y

  y = 6√6 . . . . . take the square root

8 0
2 years ago
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