(gof)(0) cannot be evaluated
<em><u>Solution:</u></em>
Given that,
A composite function is denoted by (g o f) (x) = g (f(x)).
The notation g o f is read as “g of f”
Therefore, let us find whether (gof)(0) can be evaluated or not
To find (gof)(0):
(g o f) (x) = g (f(x))
Now substitute the given value of f(x)
Now to find (gof)(0), substitute x = 0
Since 1 divided by 0 is undefined, because any number divided by 0 is undefined
(gof)(0) cannot be evaluated
Y + 8 = 4(x - 5)
distribute the 4 to both x and -5
4(x) = 4x
4(-5) = -20
y + 8 = 4x - 20
isolate the y, subtract 8 from both sides
y + 8 (-8) = 4x - 20 (-8)
y = 4x - 28
plug in the x given, if the y matches the answer given, it is the correct answer.
-8 = 4(5) - 28
-8 = 20 - 28
-8 = -8 (True)
D) (5,-8) should be your answer
hope this helps
Irrational numbers are the subset of real numbers that are not at all connected to the rest of numbers.
The subsets of real numbers are natural numbers, whole numbers, integers, rational numbers and irrational numbers.
Natural numbers are subset of whole numbers, which are subset of integers, which are subset of rational numbers. Hence, all of them are interconnected. The set of irrational numbers is the only subset of real numbers which is not associated with the rest.
For example:-
1 is a natural number, whole number, integer, rational number but not irrational number. On the other hand, is an irrational number but none of the rest.
To learn more about real numbers, here:-
brainly.com/question/551408
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Answer:
The function in the fourth option will have an axis of symmetry at x = 3.
Step-by-step explanation:
We have to choose the function from options, the graph of which has an axis of symmetry at x = 3.
The function in the fourth option will have an axis of symmetry at x = 3.
It is f(x) = x2 – 6x – 1 On a coordinate plane, a parabola opens up. It goes through (0, negative 1), has a vertex at (3, negative 10), and goes through (6, 0). (Answer)
I think it’s 12
1/3 = 4/12
1/4 = 3/12
Hope it’s correct