Answer:
Susan has suggested a correct method to calculate the amount of money
Step-by-step explanation:
Here we must check what each person is calculating. First, we consider Susan's method. She has suggested that we multiply the cost per soda, that is dollars/soda by the number of sodas required, we get the total cost.
Assuming that 18 sodas are required and each costs $0.20, the total cost according to Susan is $3.60.
John suggests we divide the cost of a 12 pack of soda by the number of sodas required. Considering a 12 pack of soda costs $12 and the same amount of sodas, 18, are required, we get that each soda costs $0.66.
Looking at these answers, we see that Susan has suggested a correct method to calculate the amount of money needed to buy a number of sodas. John has suggested the amount each person would have to contribute if everyone at the party was trying to buy a 12-pack of soda; regardless of whether more or less than a 12-pack is required.
Answer:
Step-by-step explanation:
well you start at origin 0 because there is no y-intercept so you would do rise over run up 1 over 4, 1/4 is your slope
Answer:
1/10
13/100
4/5
12/25
3/10
63/100
3/5
51/200
2/9
5/11
To prove the last 2 recurring ones:
0.222222... = x
10x = 10 * 0.22222... = 2.222222....
Notice how the decimal part of 10x is the same as for x:
10x - x = 2.2222222... - 0.222222... = 2
10x - x = 9x = 2
x = 2/9
Same procedure for the other one but times by 100 instead:
x = 0.454545...
100x = 45.454545...
100x - x = 45.454545... - 0.454545... = 45
100x - x = 99x = 45
x = 45/99 = 5/11
Answer:
Area of the triangle is 10 square units
Step-by-step explanation:
Recall that the formula for the area of a triangle is: "base x height / 2", and in this case, we can consider the triangle's base as the segment that joins the vertices (5, 4) and (5, 8) which gives a segment length of 4 units. The height of the triangle is then the distance between the third vertex (0,7) and the base, which is exactly 5 units. Then the area becomes:
Area = 4 x 5 / 2 = 10 square units.
