Answer:
Sodium - D) Malleable, soft, and shiny
Sodium is an alkalyne metals that is why they are soft and sodium can cut by knife.
Silicon - C) Has properties of both metals and nonmetals
As we know that those materials have both nonmetals and metals properties are known as metaloid.
Bromine - A) Highly reactive gas
All halogens are so reactive .Because they are high electro negative element.Bromine(Br) is a halogen element.
Argon - B) Nonreactive gas
All noble gases are stable that is why they are not reactive with ant other element.So we can say that noble gas are Nonreactive gas.Argon(Ar) is noble gas.
Answer:
1) Buoyant force, 2) sinks, 3) equilibrium, 4) fleet , 5) LIFT force
Explanation:
A body in a fluid is subjected to two forces, its weight and the thrust
sun F = B - W
the em
bid is always vertical and contrary to weight, let's analyze and complete the different situations presented
1) Buoyant force
2) sinks B <W
3) equilibrium B = W
4) fleet B> W
5) by the sum of two forces:
* Thrust, but the density of air is much less than the density of water, therefore the thrust in the air is less.
* The other force in airplanes the lift force given by the difference in the path of the air when the plane moves, which translates into a pressure difference between the upper part of the wing and the lower part, it is force is called LIFT force
Wavelength = 20 m = 0.20 m
frequency = 3*10^8 / 0.20 = 1.5 * 10^9 Hertz
Answer:
b) True. the force of air drag on him is equal to his weight.
Explanation:
Let us propose the solution of the problem in order to analyze the given statements.
The problem must be solved with Newton's second law.
When he jumps off the plane
fr - w = ma
Where the friction force has some form of type.
fr = G v + H v²
Let's replace
(G v + H v²) - mg = m dv / dt
We can see that the friction force increases as the speed increases
At the equilibrium point
fr - w = 0
fr = mg
(G v + H v2) = mg
For low speeds the quadratic depended is not important, so we can reduce the equation to
G v = mg
v = mg / G
This is the terminal speed.
Now let's analyze the claims
a) False is g between the friction force constant
b) True.
c) False. It is equal to the weight
d) False. In the terminal speed the acceleration is zero
e) False. The friction force is equal to the weight
Density = mass / volume so mass = density x volume
2 litres = 2000cm^3
mass = 1.27 x 2000 = 2540g = 2.54 kg