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3 years ago

Waves inwhich the particles vibrate at right angles to direction is called

1 answer:

5 0

When the particles of a medium are vibrating at right angles to the direction of energy transport, then the wave is a ____ wave. In transverse waves, particles of the medium vibrate to and from in a direction perpendicular to the direction of energy transport.

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An obiect of mass weighing 5,24 k acceleration due to gravity is 9 8 meters/second2 is raised to a height of 1.63 meters. What i

Julli [10]

83.79 J (using significant digits)

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3 years ago

This is the simplest type of fold where the rock bends like this:

Natasha_Volkova [10]

The answer is Monocline. And I checked it, it's correct.

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3 years ago

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Magnet A doesn't have its poles labeled, but Magnet B has a clearly labeled north and south pole. If the

dusya [7]

Answer:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

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3 years ago

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assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e

Dmitry [639]

Answer:

$9.3\cdot 10^{37}$

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

$P= \frac{E}{t}$

This means that the energy produced in the Sun each second (1 s), given the power $P=4.0\cdot 10^{26}W$ , is

$E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J$

Each p-p chain reaction produces an amount of energy of

$E_1 = 4.3\cdot 10^{-12} J$

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

$n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}$

3 0

3 years ago

A 86g ball is dropped vertically to the floor from a height of 2.87m and bounces to a height of 1.28. What is the magnitude of t

irga5000 [103]

Answer:

The impulse received by the ball from the floor during the bounce is approximately 1.11329438 m·kg/s

Explanation:

The given mass of the ball, m = 86 g = 0.089 kg

The height from which the ball is dropped, H = 2.87 m

The height to which the ball bounces, h = 1.28 m

Mathematically, we have;

Δp = F·Δt

Where;

Δp = The change in momentum = m·Δv

F = The applied force

Δt = The time of contact with the force

The velocity of the ball just before it touches the ground, v₁ = -√(2·g·H)

The velocity with which the ball leaves, v₂ = √(2·g·h)

The change in momentum, Δp = m·(v₂ - v₁)

∴ Δp = m·(√(2·g·h) - (-√(2·g·H))) = m·(√(2·g·h) +√(2·g·H) )

The impulse, Δp, received by the ball from the floor during the bounce is given as follows;

Δp = 0.089 kg × (√(2 × 9.8 m/s² × 1.28 m) + √(2 × 9.8 m/s² × 2.87 m)) ≈ 1.11329438 m·kg/s

The impulse received by the ball from the floor during the bounce, Δp ≈ 1.11329438 m·kg/s

6 0

3 years ago