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vichka [17]
4 years ago
7

The most likely theory of the formation of Earth's Moon is that it The most likely theory of the formation of Earth's Moon is th

at it formed simultaneously with Earth's formation. was formed by the gravitational capture of a large asteroid. formed from a collision of Earth with a Mars-sized object. was created from a collision scooping out the Pacific Ocean.
Physics
1 answer:
Ann [662]4 years ago
4 0

Answer:

Option (3)

Explanation:

According to researches done by the astronomers, it has been found that the earth collided with a giant Mars-size early proto-planet, whose name was 'Theia' during the Hadean era, about.5 billion years back. This collision resulted in the detachment of a considerably huge amount of material away from the earth. The remnant debris particles accumulated and gave rise to the formation of moon. The earth during that time was comprised of molten lava only, and from this collision, the earth attained its tilt of approximately 23.5°.

Thus, the correct answer is option (3).

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A gold bar 20.0kg at 35.0°c is placed in a large insulated 0.8kg glass container at 15°c and 2.0kg of water at 25°c.. calculate
Oksanka [162]

Answer:

The final equilibrium temperature is approximately 26.69 °C

Explanation:

The heat transferred, ΔQ, from a hot body to a cold one is given by the following formula;

ΔQ = m·c·ΔT

Where;

m = The mass of the body

c = The specific heat capacity of the body

ΔT = The temperature change of the body

The given mass of the gold bar, m₁ = 20.0 kg

The initial temperature of the gold bar, T₁ = 35.0 °C

The specific heat capacity of gold, c₁ = 0.13 kJ/(kg·K)

The mass of the glass container, m₂ = 0.8 kg

The initial temperature of the glass container, T₂ = 15°C

The specific heat capacity of glass, c₂ = 0.792 kJ/(kg·K)

The mass of the added water, m₃ = 2.0 kg

The initial temperature of the added water, T₃ = 25°C

The specific heat capacity of water, c₃ = 4.2 kJ/(kg·K)

The heat lost by the gold = The heat gained by the glass and the water

Let 'T' represent the temperature at the final equilibrium, we have;

m₁·c₁·ΔT₁ = m₂·c₂·ΔT₂ + m₃·c₃·ΔT₃

Where;

ΔT₁ = T₁ - T

ΔT₂ = T - T₂

ΔT₃ = T - T₃

∴ 20.0 × 0.13 × (35 - T) = 0.8 × 0.792 × (T - 15) + 2.0 × 4.2 × (T - 25)

Expanding and collecting like terms (using a graphing calculator) gives;

91 - 2.6·T = 9.0336·T - 219.504

9.0336·T + 2.6·T = 219.504 + 91 = 310.504

11.6336·T = 310.504

T = 310.504/11.6336 ≈ 26.69

The final equilibrium temperature, T ≈ 26.69 °C.

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