Let x^2−20x=10 .

Use the compound interest formulas A=P e^rt to solve the problem given. round answers to the nearest cent.

goblinko [34]

Answer:

a) $20,771.76

b) $20,817.67

c) $20,484.80

d) $20,864.52

Step-by-step explanation:

Compound Interest Formula

$\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}$

where:

A = final amount
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Part (a): semiannually

Given:

P = $15,000
r = 5.5% = 0.055
n = 2
t = 6 years

Substitute the given values into the formula and solve for A:

$\implies \sf A=15000\left(1+\frac{0.055}{2}\right)^{2 \times 6}$

$\implies \sf A=15000\left(1.0275}{2}\right)^{12}$

$\implies \sf A=20771.76$

Part (b): quarterly

Given:

P = $15,000
r = 5.5% = 0.055
n = 4
t = 6 years

Substitute the given values into the formula and solve for A:

$\implies \sf A=15000\left(1+\frac{0.055}{4}\right)^{4 \times 6}$

$\implies \sf A=15000\left(1.01375}\right)^{24}$

$\implies \sf A=20817.67$

Part (c): monthly

Given:

P = $15,000
r = 5.5% = 0.055
n = 12
t = 6 years

Substitute the given values into the formula and solve for A:

$\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{12 \times 6}$

$\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{72}$

$\implies \sf A=20484.80$

Continuous Compounding Formula

$\large \text{$ \sf A=Pe^{rt} $}$

where:

A = Final amount
P = Principal amount
e = Euler's number (constant)
r = annual interest rate (in decimal form)
t = time (in years)

Part (d): continuous

Given:

P = $15,000
r = 5.5% = 0.055
t = 6 years

Substitute the given values into the formula and solve for A:

$\implies \sf A=15000e^{0.055 \times 6}$

$\implies \sf A=20864.52$

Learn more about compound interest here:

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11111nata11111 [884]

Answer:

Step-by-step explanation:

What I can see from this are many things. First of all, the girls achieved a higher score than the boys since the girls got a higher mean then the boys. This means that if we were to take the average score of each gender, the girls got a higher score. To find the average/mean you need to find the sum of the data set then divide it with the number of data entries. The boys had a smaller range than the girls, which means that the scores the boys achieved were closer than the girls. The higher the range the more likely your data is scattered. The lower your range, the more likely your data is contained of similar numbers. You figure out the range but subtracting your highest data point from your lowest data point.

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miv72 [106K]

Answer:

9825

Step-by-step explanation:

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Find the area of the following polygons:

Art [367]

Area of ABCE:
12 x 4
= 48cm squared

Area of CDE:
To get the height of the triangle, you subtract 4 from 10.

10 - 4 = 6cm
Base = 12 cm

12 x 6 = 72cm

72 divided by 2
= 36cm squared.

48 + 36 = 84cm squared.

(if it’s asking individual areas, then it’s 48cm and 36cm)

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Answer:

w = 2/9.

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Let ​ x^2−20x=10 .​

Let x^2−20x=10 .