What is the answer for this problem
1 answer:
You might be interested in
Hello!
Let's think about the denominators we have. A seventh goes on forever in no specified order. A fifth an a fourth have set decimal values, 0.2 and 0.25, so they are not repeating decimals. A ninth is 0.111111..., it repeats like this forever in a specified order. Therefore, 2/9, or 0.222222...., would be a repeating decimal.
Therefore, our answer is .
I hope this helps!
Answer:
Step-by-step explanation:
To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.
(I use the notation x|y to denote that x divides y)
(A)
(B)
In this case, it is easier to also factor the divisor to primes:
Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:
