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Tju [1.3M]
3 years ago
10

What is the answer for this problem

Mathematics
1 answer:
solong [7]3 years ago
6 0
I don't know what your story is, but in a story, usually a problem would build tension.

Hope this helps!! :)
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The made 9 pounds of fudge . The fudge was separated into 3/4 pound blocks . They sell each block for $6.50 .if they sell all th
Flauer [41]
Number 16, he put 1/2 of his money into his savings and took the rest to spend. So fraction of his amusement park money he spent on rides and popcorn is (1/5 + 3/4) x 1/2 = 19/40 <=> A

Each 3/4 pound block for $6.50. So each pound block will be $6.50 x 4/3 = 26/3. They have 9 pounds of fudge, money they will make is 26/3 x 9 = $78
3 0
3 years ago
What is 0.5 + -1 1/2
lakkis [162]

-1 is your answer.........


6 0
3 years ago
Answer fast!! With explanation pls
Zepler [3.9K]
D is equivalent because brackets don’t change anything here
4 0
3 years ago
Read 2 more answers
Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re
kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read 13\frac{3}{4} pages in \frac{1}{4} of an hour.

Therefore, pages read by Zander in 1 hour = \frac{\text{Total pages read}}{\text{Total time taken}}

= \frac{13\frac{3}{4}}{\frac{1}{4}}

= \frac{55}{4}\times \frac{4}{1}

= 55 pages per hour

Sydney read 43\frac{1}{3} pages in \frac{2}{3} of an hours.

Pages read by Sydney in 1 hour = \frac{43\frac{1}{3}}{\frac{2}{3} }

= \frac{130}{3}\times \frac{3}{2}

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0
3 years ago
Simplify by expressing fractional exponents instead of radicals
igomit [66]

Answer:

a^{\frac{1}{2}}b^{\frac{1}{2}}

Step-by-step explanation:

Given:

The expression in radical form is given as:

\sqrt{ab}

We need to express this in fractional exponent form.

We know that,

\sqrt a=a^{\frac{1}{2}}

Also, \sqrt{ab}=\sqrt a\times \sqrt b

Now, clubbing both the properties of square root function, we can rewrite the given expression as:

\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}

So, the given expression in fractional exponents form is a^{\frac{1}{2}}b^{\frac{1}{2}}.

3 0
3 years ago
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