The solution to the problem is as follows:
let y = asinx + bcosx
<span>
dy/dx = acosx - bsinx </span>
<span>
= 0 for max/min </span>
<span>
bsinx = acosx </span>
<span>
sinx/cosx = a/b </span>
<span>
tanx = a/b </span>
<span>
then the hypotenuse of the corresponding right-angled triangle is √(a^2 + b^2) </span>
<span>the max/min of y occurs when tanx = a/b </span>
<span>
then sinx = a/√(a^2 + b^2) and cosx = b/√(a^2 + b^2) </span>
<span>
y = a( a/√(a^2 + b^2)) + b( b/√(a^2 + b^2)) </span>
<span>
= (a^2 + b^2)/√(a^2 + b^2) </span>
<span>
= √(a^2 + b^2)</span>
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Answer:
-1.92 cm³
Step-by-step explanation:
The formula for the volume of a cube in terms of side length is ...
V = s³
Then the first-order approximation of volume for a small change ∆s in side length is ...
V(s +∆s) ≈ V(s) + V'(s)·∆s
and the change in volume is ...
∆V ≈ V(s +∆s) -V(s) = V'(s)·∆s
The derivative V'(s) is ...
V'(s) = 3s²
so the change in volume for s = 8 cm and ∆s = -0.01 cm is ...
∆V ≈ 3s²·∆s = 3(8 cm)²(-0.01 cm) = -1.92 cm³
<span>0.00996 would be it I just took a quiz like that but good luck</span>
Infinitely many solutions means that you have the same thing on both sides of the equation no matter what value of x you plug in, right?
We just need both sides to be 3x then, correct?
If a were equal to 3 and b were equal to 0, we'd have
3x = (3)x + 0
Which is essentially 3x = 3x
So that means a = 3 and b = 0 must work!
Let's say x = 5
3(5) = 3(5) + 0
15 = 15 + 0
15 = 15
That means that a = 3 and b = 0 is your final answer :)