The equation that describes the which gives the area of the pen, A, as a function of x, the length of fence parallel to the barn is A = 130x - x²
<h3>How to find area of a rectangle?</h3>
The pen is rectangular. Therefore,
area of a rectangle = lw
where
Therefore,
perimeter = 2w + l
perimeter = 2w + x
130 = 2w + x
130 - x = 2w
w = 65 - 1/ 2 x
A = xw
A = x(65 - 1/ 2 x)
A = 65x - 1 / 2 x²
Therefore, the function that represents A, the area of the pen is as follows:
A = 130x - x²
learn more on rectangle here: brainly.com/question/12685460
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The correct answer is A. Longing I know because I just finished the quiz.
Y=radical 3
just cancel out the 2 on both sides
We have to represent the fraction
in two different ways.
Let us multiply the numerator and denominator of the given fraction by '2'.
Therefore, 
Therefore,
is the first way to represent the given fraction.
Now, Let us multiply the numerator and denominator of the given fraction by '3'.
Therefore, 
Therefore,
is the second way to represent the given fraction.
Therefore,
and
are the different ways to represent the fraction
.
Answer:
The supplier becomes less accurate than they otherwise would have tried to claim. A further explanation is below.
Step-by-step explanation:
According to the provider, this same width of that same confidence interval would be as follows:
= 
= 
Depending on the input observed, the width including its confidence interval would be as follows:
= 
= 
As even the width of that interval again for survey asserted > the width including its confidence interval according to the provider's statement, we could conclude that such is the appropriate reaction.