Answer:
42.85714285%
OR
Simplified: 42.86%
Step-by-step explanation:
Make sure you Multiply
3/7 times 100
= 42.86%
Hope this helps!
Hey there! :)
Answer:
d ≈ 3.49 units
Step-by-step explanation:
Use the distance formula for polar coordinates to determine the distance:
(The '0' is supposed to be theta)
Plug in the values given in the question. Convert radians to degrees to simplify the process.
217π/180 = 217°
-23π/36 = -115°.
Therefore:

Begin simplifying:


Solve:

d ≈ 3.49 units
Answer:
The 95% confidence interval for the mean number of ounces of ketchup bottle is (23.8, 24.2).
Step-by-step explanation:
The complete question is:
Suppose that a restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average, with a standard deviation of 0.8 ounces. If you took a sample of 49 bottles of ketchup, what would be the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample?
Solution:
The (1 - <em>α</em>)% confidence interval for the population mean is:

The information provided is:

The critical value of <em>z</em> for 95% confidence level is:

*Use a <em>z</em>-table.
Compute the 95% confidence interval for the mean number of ounces of ketchup per bottle as follows:


Thus, the 95% confidence interval for the mean number of ounces of ketchup bottle is (23.8, 24.2).
3.48 because 1.2•2.9 = 3.48 therefore cliffs rabbit weighs3.48 kilograms