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elixir [45]
3 years ago
9

Solve the equation 36w = 16w + 24

Mathematics
2 answers:
Umnica [9.8K]3 years ago
4 0
=24/20 thus the answer is 1.2
beks73 [17]3 years ago
3 0
36w-16w=24
20w=24
W=1.2
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What's 3/7 as a percent​
Vikentia [17]

Answer:

42.85714285%

OR

Simplified: 42.86%

Step-by-step explanation:

Make sure you Multiply

3/7 times 100

= 42.86%

Hope this helps!

5 0
4 years ago
Which number line shows the solution to this compound inequality?<br><br> 0 ≤ -2x + 6 &lt; 16
Mariana [72]
The awnser too this one is -5
8 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Fiesta28 [93]

Hey there! :)

Answer:

d ≈ 3.49 units

Step-by-step explanation:

Use the distance formula for polar coordinates to determine the distance:

d = \sqrt{r_{1} ^{2}+r_{2} ^{2}-2r_{1}r_{2}cos(0_{1}- 0_{2} )   } (The '0' is supposed to be theta)

Plug in the values given in the question. Convert radians to degrees to simplify the process.

217π/180 = 217°

-23π/36 = -115°.

Therefore:

d = \sqrt{7 ^{2}+5 ^{2}-2(7)(5)cos(217-(-115) )   }

Begin simplifying:

d = \sqrt{74-70cos(332)   }

d = \sqrt{74-61.81   }

Solve:

d = \sqrt{12.19  }

d ≈ 3.49 units

6 0
4 years ago
What would be the approximate 95% confidence interval for the mean number of ounces of catchup bottle in the sample
Alex777 [14]

Answer:

The 95% confidence interval for the mean number of ounces of ketchup bottle is (23.8, 24.2).

Step-by-step explanation:

The complete question is:

Suppose that a restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average, with a standard deviation of 0.8 ounces. If you took a sample of 49 bottles of ketchup, what would be the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample?

Solution:

The (1 - <em>α</em>)% confidence interval for the population mean is:

CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

The information provided is:

\bar x=24\\\sigma=0.8\\n=49\\\text{Confidence Level}=95\%

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the mean number of ounces of ketchup per bottle as follows:

CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

     =24\pm1.96\cdot \frac{0.80}{\sqrt{49}}\\\\=24\pm 0.224\\\\=(23.776, 24.224)\\\\\approx (23.8, 24.2)

Thus, the 95% confidence interval for the mean number of ounces of ketchup bottle is (23.8, 24.2).

3 0
3 years ago
Charlie has an adult Netherlands dwarf rabbit that weighs 1.2 kilograms. Cliff's adult Angora rabbit weighs 2.9 times as Charlie
qwelly [4]
3.48 because 1.2•2.9 = 3.48 therefore cliffs rabbit weighs3.48 kilograms
3 0
3 years ago
Read 2 more answers
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