Answer:
a) 4/27
b) 1/3
c) 6/27
Step-by-step explanation:
HI!
a)
The event A has only one member:
T T H
Therefore:
P(A) = P(T)P(T)P(H) = (2/3)(2/3)(1/3) = 4/27
b)
For event B, we are only interested in the last toss
x x H
Since the first two tosses are not important for event B they do not contribute to P(B)
P(B) = 1 * 1* P(H) = 1/3
c)
The following are elements of C:
H H T
H T H
T H H
Therefore:
P(C) = P(HHT) + P(HTH) + P(THH)
We can easily see that the probability of the three members is the sam:
P(HHT) = (1/3) (1/3) (2/3) = 2/27
P(HTH) = (1/3) (2/3) (1/3) = 2/27
P(THH) = (2/3) (1/3) (2/3) = 2/27
Therefore:
P(C) = 3 P(HHT) = 6/27
I would help you, but sadly, i cannot read what the paper states.
Since
simple interest = Pit
where
P=principal
i=interest rate
t=time,
we see that the equation is one of joint variation, meaning that simple interest is a direct variation with each variable, P, i or t.
Therefore if ANY one of the variables is doubled, the simple interest is also doubled.
This problem can be solved easily. The equation states that
y is a function of x. Since this is the case, then we can get the initial value
of the function when x = 0. Therefore by substitution:
y = - 2 x -5
y = - 2 (0) – 5
y = -5 (ANSWER)