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Andrej [43]
3 years ago
6

I am equation of the line that passes through the point (2,3) with slope 3 please answer

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

\huge{\boxed{y-3=m(x-2)}}

Point-slope form is y-y_1=m(x-x_1), where m is the slope and (x_1, y_1) is a point on the line.

Substitute the values. \boxed{y-3=m(x-2)}

<em>Note: This is in point-slope form. Let me know if you need a different form. Also, if you have any more problems similar to this, I encourage you to try them on your own, and ask on here if you are having trouble.</em>

Aleks04 [339]3 years ago
5 0

Answer:

y-3 = 3(x-2)  point slope form

y = 3x-3  slope intercept form

Step-by-step explanation:

We can use the point slope form of the equation for a line

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is the point

y-3 = 3(x-2)  point slope form

If we want the line in slope intercept form

Distribute

y-3 = 3x-6

Add 3 to each side

y-3+3 = 3x-6+3

y = 3x-3  slope intercept form

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Given:

In triangle ABC, point D is the centroid, and BD = 6.

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