Answer: A statistical question anticipates variability in the response and can be answered by collecting data.
Step-by-step explanation:
Answer: 13300
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Work Shown:
A = event that it rains
B = event that it does not rain
P(A) = 0.30
P(B) = 1-P(A) = 1-0.30 = 0.70
Multiply the attendance figures with their corresponding probabilities
- if it rains, then 7000*P(A) = 7000*0.30 = 2100
- if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200
Add up the results: 2100+11200 = 13300
This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.
<em>《</em><em>°</em><em>♡</em><em> </em><em>i think that the answer to this question is -5 1/3</em><em> </em><em>(</em><em>-16</em><em>/</em><em>3</em><em>)</em><em> </em><em>hope this helps!</em><em> </em><em>♡</em><em>°</em><em>》</em>
Based on lifelike statistics, I would say they got more sleep than about 8-10 hours.
Answer:
37 1/8
Step-by-step explanation:
The problem probably assumes direct variation
y=kx
IF so, then plug in the values and solve for k
27=k(8)
k = 27/8
y= (27/8)x. Now let x = 11
y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8
y = 37 1/8
the problem is making some assumption about the relation between x and y. The simplest assumption that's likely is direct variation, that x and y are linearly related. The graph is a straight line through the origin with slope = 27/8
