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Anna35 [415]
3 years ago
14

For the following geometric sequence find the explicit formula. {12, -6, 3, ...}

Mathematics
2 answers:
vivado [14]3 years ago
7 0
It's geometric sequence where a_1=12, q=-\dfrac{1}{2}

So a_n=12\cdot\left(-\dfrac{1}{2}\right)^{n-1}

enyata [817]3 years ago
4 0

Answer:

a_n=12*(-\frac{1}{2})^{n-1}

Step-by-step explanation:

We are asked to write an explicit formula for the given geometric sequence.

We know that explicit formula for a given geometric sequence is in form a_n=a_1*r^{n-1}, where,

a_n=\text{ nth term of sequence},

a_1=\text{ 1st term of sequence},

r = Common ratio.

n = Number of terms of sequence.

To find common ratio, we will divide any term of our given sequence by its previous term.

r=-\frac{-6}{12}=-\frac{1}{2}

a_n=12*(-\frac{1}{2})^{n-1}

Therefore, our required formula would be a_n=12*(-\frac{1}{2})^{n-1}.

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Which of the following shows that EFGH is a parallelogram for y=7 and z=9?
Anna35 [415]

Option B: m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Explanation:

Option A: m \angle E=m \angle F=60^{\circ} and m \angle G=120^{\circ} so \angle G is supplementary to both \angle E and \angle F, so EFGH is a parallelogram

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we get, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Thus, m \angle E\neq m \angle F because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B:  m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Hence, Option B is the correct answer.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

To determine the angles, let us substitute z=9 in  m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ}

Thus, m \angle F=m \angle G=120^{\circ}

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Adding the angles E and G, we have,

m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

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