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4 years ago

Megan is checking her tax bill for the last year.

Mathematics

1 answer:

steposvetlana [31]4 years ago

7 0

Answer:

£53205

Step-by-step explanation:

The computation is shown below:

£11,000 = $0

In excess of £11,000 and up to £43,000 the tax rate is 20%

So the tax amount is

= (£43,000 - £11,000) × 20%

= £6,400

In excess of £43,000 and up to £150,000 the tax rate is 40%

So the tax amount is

= (£150,000 - £43,000) × 40%

= £42,800

And, the remaining amount is

= (£158,900 - £150,000) × 45%

= £4,005

So the total tax paid amount is

= £0 + £6,400 + £42,800 + £4,005

= £53,205

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Please help me!!! 30 minutes left

Lesechka [4]

Option D:

$\frac{25 a^{9} b^{10} }{6 }$ is equivalent to the given expression.

Solution:

Given expression:

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}$

To find which expression is equivalent to the given expression.

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}$

Using exponent rule: $(ab)^m=a^mb^m$

$$=\frac{5^3 a^3 b^{3}}{30 a^{-6} b^{-7}}$

Using exponent rule: $\frac{1}{a^{m}}=a^{-m}, \quad \frac{1}{a^{-m}}=a^{m}$

$$=\frac{125 a^3 b^{3}a^{6} b^{7}}{30 }$

$$=\frac{125 a^3 a^{6} b^{3} b^{7}}{30 }$

Using exponent rule: $a^{m} \cdot a^{n}=a^{m+n}$

$$=\frac{125 a^{3+6} b^{3+7} }{30 }$

$$=\frac{125 a^{9} b^{10} }{30 }$

Divide both numerator and denominator by the common factor 5.

$$=\frac{25 a^{9} b^{10} }{6 }$

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}=\frac{25 a^{9} b^{10} }{6 }$

Therefore, $\frac{25 a^{9} b^{10} }{6 }$ is equivalent to the given expression.

Hence Option D is the correct answer.

4 0

3 years ago

Find the value of X?

il63 [147K]

Answer:

C.92

Step-by-step explanation:

I don't know just random picking sorry

6 0

3 years ago

I need an expert and ill comment the other question I need u to look up

kodGreya [7K]

Answer:

Step-by-step explanation:

I’m not an expert but I think it might be 43 goes with 430 430 goes with 0.43 and 4.3 goes with 43 and 4300 goes with 43

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4 years ago

Read 2 more answers

Meg found 59 seashells on the beach, she gave sam some of her seashells. she has 12 seashells left. how may seashells did she gi

algol13

Answer:

Meg gave Sam 47 seashells

Step-by-step explanation:

59-12= 47

checking my work: 47+12= 59

5 0

3 years ago

Question 1

Vlad1618 [11]

Answer:

1 . Segment EF is twice as as segment AB

4. The length of segment EH is 16 units

Step-by-step explanation:

Quadrilateral EFGH was created by increasing all the length segments of quadrilateral ABCD proportionally by multiplying the lengths of ABCD by a scale factor.

Scale factor used = GH/CD = 12/6 = 2

Let's examine each statements to see which is true or not true:

1 . "Segment EF is twice as as segment AB."

This is true. EF corresponds to AB. Since scale factor = 2, length of any segment of quadrilateral EFGH would be twice the length of quadrilateral ABCD.

2. "Segment CD is twice as long as segment FG."

This is not true, because segment CD does not correspond to segment FG. Segments in EFGH are twice as the corresponding segments in ABCD.

3. "The measure of angle HEF is twice the measure of the angle DAB."

This is not true. Shape remains the same. Only the size changes.

4. "The length of segment EH is 16 units".

This is true because EH is twice the corresponding segment in ABCD, which is 2"AD = 2*8 = 16 units.

5. "The area of EFGH is twice the are of ABCD"

This is not true. Area of the scaled copy would be times 4 of the original figure.

4 0

4 years ago