All categories

3 years ago

Melanie draws with great fervor, using up pencils at an incredible rate: 14 pencils every

1 answer:

5 0

4 pencils . 4/9 of an hour = 4/9 of 60 minutes = 4/9 * 60 = 80/3 minutes
x pencils = ? . one hour = 60 minutes

14 * 60 = 80/3 * x /*3
14 * 60 * 3 = 80 * x
80 * x = 2520 /80
x = 2520 / 80
x = 31.5 pencils

The result would be 32 pencils in one hour.

You might be interested in

What is PA Enter your answer in the box

SSSSS [86.1K]

Answer:

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : $PK^{2}=PE^{2}+KE^{2}$

⇒ $PE^{2}=PK^{2}-KE^{2}$

⇒ $PE=\sqrt{PK^{2}-KE^{2} }$

⇒ $PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }$

⇒ $PE=3$

Therefore, $PA=3$

3 0

3 years ago

At a rock concert, the ratio of girls to boys is 3:7. If there are 360 more boys than girls, how many girls are at the concert?

bixtya [17]

You could understand the ration as parts: the total number of parts was 3+7=10.

So girls were 3/10 parts and boys 7/10 parts. The difference was 7-3=4 parts. this difference is equal to 360, so each part is 90 (4*90 =360).

so girls are "3 parts" and each part is 90, then the number of girls is 3*90=270.

4 0

3 years ago

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that 5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

 $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

Help with math word problem, 10 points

Feliz [49]

I hope this helps you

6 0

3 years ago

34 rounded to the nearest 10 with a 69 degree angle

givi [52]

Question 2:

During his workouts last week, Allen jogged the same amount of time each day for 6 days. Use the following information to determine the number of minutes Allen jogged each day:

During each workout, he jogged and he rode his bike.

He rode his bike for 45 minutes each day.

He worked out for a total of 360 minutes last week.

What is the number of minutes that Allen jogged each day last week? Enter your answer in the box below. PLS HELP ME I DONT WANNA GET A F PLSSSSSSSSS

3 0

3 years ago

Read 2 more answers