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olchik [2.2K]
3 years ago
11

Carlene is selling T-shirts for a fundraiser. The T-shirts cost $20.50 each. To date, she has raised $800. Her goal is to raise

more than $10,640. How many more T-shirts, x, does Carlene need to sell to reach her goal?
Mathematics
2 answers:
Xelga [282]3 years ago
3 0
Carlene needs to sell 480 shirts to meet her goal.
aleksandrvk [35]3 years ago
3 0
 I believe you have to divide i had this question yesterday actual and i got it right try it then tell me what you got. <span />
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Precipitation for the month of March was 6 1/2 inches less than average. In April, the precipitation was 2 3/8 inches less than
lidiya [134]

Answer:

See explanation.

Step-by-step explanation:

It is subtraction

whole numbers, then numerators.

6 - 2 = 4

1/2 - 3/8

= 4/8 - 3/8 (1/2 = 4/8)

= 1/8

= 4 1/8

hope this helps!

8 0
2 years ago
Read 2 more answers
Decide which of the two points on the graph of the line<br> X=0<br> A. 0,7<br> B. -4,0
MrMuchimi
When x = 0

A. 0, 7 is your answer

hope this helps
4 0
3 years ago
Suppose that f: R --&gt; R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
2 years ago
At the bookstore, 40 copies of a popular paperback book fit perfectly on a 5-foot shelf. How many copies of this book would fit
Ierofanga [76]

Answer:

64 books

Step-by-step explanation:

The first step is to find the number of books that will fit in the shelve per foot

= 40/5

= 8

Therefore the number of books that will fit perfectly in 8-foot shelf can be calculated as follows

= 8×8

= 64

Hence 64 books would fit in 8-foot shelf

5 0
3 years ago
A company estimates that it will sell ????(x) units of a product after spending x thousand dollars on advertising, as given by ?
zepelin [54]

Answer:

(11\frac{1}{3},20)

Step-by-step explanation:

If the Number of Sales of x units, N(x) is defined by the function:

N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40

N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}

Next, we text the critical points and the end points of the interval to see where the derivative is increasing.

N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600

Thus, the rate of change of sales N'(x) is increasing in the interval (11\frac{1}{3},20) on 10≤x≤40.

7 0
2 years ago
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