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ludmilkaskok [199]
3 years ago
14

Determine the surface area of the rectangular prism below

Mathematics
2 answers:
lianna [129]3 years ago
8 0
Where is the rectangle? Also just do H*W*L u will get the answer
Margaret [11]3 years ago
4 0
Were is the rectangle
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If i have 17 pills of xanax and take 6 how many do I have left
horsena [70]

17-6=11

answer is eleven

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Which of the following functions is the inverse of this function?
kykrilka [37]

Answer:c

Step-by-step explanation:

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3 years ago
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Find the distance between the two points rounding to the nearest tenth (if necessary).
Vaselesa [24]

Hey there! I'm happy to help!

Imagine the line that is created when you connect the two points (the distance between the two points).

You can create a right triangle where this distance is the hypotenuse where the two legs are the change in x and y. So, if you take those changes in x and y, you can use the Pythagorean Theorem (a²+b²=c²) to find the distance between the two points, which is the hypotenuse.

Our change in x is 9 because 9-0 is 9.

We square it

9²=81

Our change in y is 5 as -1-(-6) or -1+6 is 5.

5²=25

We add these.

81+25=106

We square root and round to the nearest tenth.

√106≈10.3

So, our distance is 10.3.

This Pythagorean Theorem method actually gives us a formula called the distance formula that you can use to find the distance between points.

\sqrt{(x_{2} -x_{1})^2+(y_{2}-y_{1})^2}

Have a wonderful day and keep on learning! :D

8 0
3 years ago
What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0
3 years ago
If A • B*2 = 1.8 x 10*-7, and C•B/D = 7.2 x 10*-4, find the value of A•D*2/C*2
Charra [1.4K]

Answer:

-7.2

Step-by-step explanation:

8 0
3 years ago
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