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Lorico [155]
2 years ago
15

Alex says that there is no numbers between 1/3 and 1/4 . Why might he think that and what would you tell him? Is there a number

that falls between these?
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
8 0

Answer:

<em>Why might he think that and what would you tell him?</em>

He thought perhaps that numbers were formed by rational numbers of the form \frac{1}{x}, where x\in \mathbb{N}. I would tell him that there are rational numbers \frac{y}{z}, such that \frac{1}{x}\le \frac{y}{z} \le \frac{1}{x+1}, where x, y, z \in \mathbb{N}.

<em>Is there a number that falls between these?</em>

\frac{7}{24} is a rational number between \frac{1}{3} and \frac{1}{4}.

Step-by-step explanation:

<em>Why might he think that and what would you tell him?</em>

He thought perhaps that numbers were formed by rational numbers of the form \frac{1}{x}, where x\in \mathbb{N}. I would tell him that there are rational numbers \frac{y}{z}, such that \frac{1}{x}\le \frac{y}{z} \le \frac{1}{x+1}, where x, y, z \in \mathbb{N}.

<em>Is there a number that falls between these?</em>

Indeed, the average number of \frac{1}{3} and \frac{1}{4}, for instance. That is:

\frac{y}{z} = \frac{\frac{1}{3}+\frac{1}{4}  }{2}

\frac{y}{z} = \frac{\frac{7}{12} }{2}

\frac{y}{z} = \frac{7}{24}

\frac{7}{24} is a rational number between \frac{1}{3} and \frac{1}{4}.

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From the given table, the annual premium rate as a percentage of value insured a person at age 35 has to pay is 0.14%.

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Reasons:

The data in the table are presented as follows;

\begin{tabular}{|c|c|c|}Age&Annual Insurance Premiums (per \$1,000 of face value)&\\&10-Year Term &\\&Male&Female\\35&1.40&1.36\\40&1.64&1.59\\45&2.07&2.01\end{array}\right]

From the above table, we have that the amount a 35 year old without health issues will pay per $1,000 is $1.40

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The amount more Bernard has to pay = $185.15 - $161 = $24.15 ≈ <u>$24</u>

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brainly.com/question/3053945

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