1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lubov Fominskaja [6]
3 years ago
13

Please help show work for part b it well help a lot and do part a too thanks

Mathematics
2 answers:
rjkz [21]3 years ago
7 0
T=32+0.33c
b.t=32+0.33c
t=32+0.33(10)
t=32+(3.30)
t=35.30
Lostsunrise [7]3 years ago
4 0
Cost to print 80 cards= $32
Additional Card = $0.33

Total cost = t
additional number of cards = c

------------------------------------------------------------------------
 Answer : Equation : t = 32 + 0.33c
------------------------------------------------------------------------

90 - 80 = 10
There are 10 additional cards

t = 32 + 0.33(10)
t = 32 + 3.3
t = $35.30

------------------------------------------------------------------------
Answer : Total cost of printing 90 cards = $35.30
------------------------------------------------------------------------
You might be interested in
WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
ad-work [718]

Answer:

Well Where are the graphs

Step-by-step explanation:


7 0
2 years ago
Read 2 more answers
PLEASEEEEEEEEEEEEEEEEEEEEE answer this today thank u
Lostsunrise [7]

Answer:

see explanation

Step-by-step explanation:

f(x) × g(x)

= 11(123x - 40) ← distribute

= 1353x - 440

Substitute x = - 4 into the product

= (1353 × - 4) - 440

= - 5412 - 440

= - 5852

7 0
3 years ago
A store sells black ink pens for $5 and red ink pens for $4. John wishes to buy 20 pens but doesn’t wish to spend more than $92.
Zina [86]

Answer:  4r + 5(20-r) \le 92

=======================================

Explanation:

r = number of red pens

4r = cost of buying r red pens

example: if r = 10, then 4r = 4*10 = 40 is the total cost of buying 10 red pens

If John buys r red pens, then he must buy 20-r black pens so that r and 20-r add to 20.

John buys 20-r black pens, and at $5 each, so it will cost 5(20-r) dollars for just the black pens alone.

In total, John spends 4r + 5(20-r) dollars for all the pens (red & black)

We want $92 be the most he spends. This is the ceiling or highest value possible.

Therefore,

4r + 5(20-r) \le 92

--------------------

Extra info:

If you want to solve for r, then

4r + 5(20-r) \le 92

4r + 5(20)+5(-r) \le 92 distribute

4r + 100 - 5r \le 92  

100 - r \le 92

100-r+r \le 92+r add r to both sides

100 \le 92+r

100-92 \le 92+r-92 subtract 92 from both sides

8 \le r

r \ge 8

So John must buy at least 8 red pens. The most he can buy is 20 red pens since he wants 20 pens total.

8 0
3 years ago
18% top for a $30 meal
irakobra [83]

Answer:

the end is 24.6 because 30-18% is equal to 24.6

4 0
3 years ago
Choose the best decimal to repersent 3 5/9
Mandarinka [93]

Answer:

3.5 repeating

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • What is thw equivalent ratio to 204/306
    13·1 answer
  • <img src="https://tex.z-dn.net/?f=simplify%20%5C%3A%20%28%20%5Cfrac%7B81%7D%7B16%7D%20%29%20%7B%20%7D%5E%7B%20%5Cfrac%7B%20-%203
    5·1 answer
  • Solve -4.8=d-3.9<br><br>Enter only the value of the variable
    5·2 answers
  • Hoodies were on sale for 20% off of the original price. Hyde bought a hoodie on sale that had an original price of $74.00. The s
    8·2 answers
  • (1/8)b -9 = -4. could anyone please help me out I'm having trouble​
    9·1 answer
  • Find the number which when added to 10 times itself gives 264
    5·1 answer
  • First 1 i got the answer but i want the 2
    13·1 answer
  • Translate this phrase into an algebraic expression.
    15·2 answers
  • Please help me with this D:
    10·1 answer
  • Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!