We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
<span>(-7) = e/3 + 14
Subtract 14 on both sides
-7 - 14 = e/3 + 14 - 14
-21 = e/3
Multiply by 3 on both sides
-21 * 3 = e/3 * 3
-63 = e</span>
Answer: n+2
Two lawns more than last week so two more than something with n being that something is; n+2
Answer:
(2)/(3) =( 4)/( 3+x)
Cross multiply
2*(3+x)= 4*3
Solve bracket
6+2x=12
Subtract 6 from both sides
2x=6
Divide both sides by 2
x=3
Hope it helps :-)
Answer:
m=9
Step-by-step explanation:
11-9m=-70
-11 -11
-9m = -81
divide both sides by -9 and you get m=9
