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3 years ago

10

What is a the gcf of 8

2 answers:

Mariulka [41]3 years ago

7 0

Answer:

8

Step-by-step explanation:

factors of 8: 1,2,4,8

GCF=8

liraira [26]3 years ago

6 0

Answer:

Step-by-step explanation:

4

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Two trucks started toward each other at the same time from towns 500 km apart. One truck traveled at a rate of 65 km

lawyer [7]

Answer: 4 hrs

Step-by-step explanation: D=RT

500=(65+60)T

500=125T

T=500/125

T=4 HOURS THEY'L MEET.

8 0

3 years ago

6. Joe runs 3/4 mile in 1/2 hour. Find his average speed in miles per hour.

son4ous [18]

Answer:

1.5 MPH

Step-by-step explanation:

3/4 = 0.75

3/4 x 2 = 0.75 x 2 = 1.5

3 0

3 years ago

7 A triangular sail has a base length of 2.5 av-ea of the is 3.75 square meters How tan is the A , , , ,. , , ,, .. -.

zavuch27 [327]

The anser is 6.25. Can you help me on mines?

7 0

3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

In the figure, AB is divided into equal parts. The coordinates of point A are (2, 4), and the coordinates of point Bare (10,6).

olasank [31]

Answer: D = 4, 4.5

E = 5, 4.75

H = 8, 5.5

I = 9, 5.75

Step-by-step explanation:Gang

4 0

3 years ago