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PolarNik [594]
3 years ago
12

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

RAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Mathematics
1 answer:
lianna [129]3 years ago
7 0

Answer:

Its 268.08 hope this helps

Step-by-step explanation:

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How to solve 93+(68+7) using the properties.
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Do the (68+7) = 75 then do 75+93=168
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A line passes through the point 6, -8 and has a slope of -3/2
rewona [7]

Answer: y=-3/2x+-8

Step-by-step explanation:

6 0
3 years ago
The polynomial x3 + 4x2 – 9x – 36 has 4 terms. Use factoring by grouping to find the correct factorization.
adell [148]
<span>x3 + 4x2 – 9x – 36

= x^2( x + 4) - 9(x + 4)

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6 0
4 years ago
Read 2 more answers
How to get the answers?​
beks73 [17]

By inclusion/exclusion,

n(P' \cup Q) = n(P') + n(Q) - n(P' \cap Q)

We have

n(\xi) = n(P) + n(P') \implies n(P') = 28 - n(P)

so that

n(P'  \cup Q) = (28 - n(P)) + n(Q) - 2n(P) = 28 - 3n(P) + n(Q)

Now,

n(\xi) = 28 \implies n(P \cup Q) = 28 - 7 = 21

and by inclusion/exclusion,

n(P \cup Q) = n(P) + n(Q) - n(P \cap Q)

Decompose Q into the union of two disjoint sets:

Q = (P \cap Q) \cup (P' \cap Q)

Since they're disjoint,

n(Q) = n(P\cap Q) + n(P'\cap Q) \implies n(Q) = n(P\cap Q) + 2n(P)

\implies n(P \cup Q) = n(P) + (n(P\cap Q) + 2n(P)) - n(P \cap Q)

\implies 21 = 3n(P)

\implies n(P) = 7

From the Venn diagram, we see there are 3 elements unique to P - by the way, this is the set P \cap Q' - so n(P\cap Q) = 7-3 = 4, and it follows that

n(Q) = n(P\cap Q) + 2n(P) = 4 + 2\times7 = 18

Finally, we get for (a)

n(P' \cup Q) = 28 - 3n(P) + n(Q) = 28 - 3\times7 + 18 = \boxed{25}

For (b), we have by inclusion/exclusion that

n(P \cup Q') = n(P) + n(Q) - n(P \cap Q') = 7 + 18 - 3 = \boxed{22}

5 0
2 years ago
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