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By inclusion/exclusion,
We have
so that
Now,
and by inclusion/exclusion,
Decompose into the union of two disjoint sets:
Since they're disjoint,
From the Venn diagram, we see there are 3 elements unique to - by the way, this is the set
- so
, and it follows that
Finally, we get for (a)
For (b), we have by inclusion/exclusion that