The answer is 20.
5*10-5*6=50-30=20
First, let's declare a variable
x = # of students
Now, let's create an equation to model the problem.
x * 0.273 = 125
Divide both sides by 0.273
x = 457.8 = 458 students.
Note, I rounded to the nearest whole number.
120° because 155-35=120 since IJZ is inside the IJK so you would have to subtract the ZJK from the IJZ.
X=6 is the answer for the problem
4.3 x 10⁻⁵ Liters
0.043 mL
4.3 x 10⁻² mL
