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Slav-nsk [51]
3 years ago
10

Find an equation of the curve that passes through the point (0, 4) and whose slope at (x, y) is x/y.

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0
1/2y^2=1/2x^2+8. The curve's slope at (x,y) is x/y, so dy/dx=x/y. To solve this differential equation, rearrange it to: y*dy=x*dx, and by integrating both sides, we get 1/2y^2=1/2x^2+C (some constant). Plug in (0,4) into this equation, 8=0+C, so C=8. The curve's equation is 1/2y^2=1/2x^2+8.
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Semenov [28]
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<span> 3.1 </span>  <span> x6</span> divided by <span>x12 = x(6 - 12) = x(-6) = 1/<span>x6</span></span>

Dividing exponential expressions :

<span> 3.2 </span>  <span> y12</span> divided by <span>y20 = y(12 - 20) = y(-8) = 1/<span>y8</span></span>

<span>Equation at the end of step  3  :</span><span> 27 4 • —————— 16x6y8 </span><span>Step  4  :</span>Final result :<span> 27 ————— 4x6y<span>8</span></span>
6 0
3 years ago
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makkiz [27]

Answer:

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Step-by-step explanation:

Hello! Thanks for letting me answer your question! If you have any more questions feel free to ask me! If not, Have a WONDERFUL day and Please don't forget to consider making me Brainliest on your question today!

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6 0
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