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ehidna [41]
4 years ago
9

PLEASE HELP ARGENt!!!!!!!!!!!!

Mathematics
1 answer:
jekas [21]4 years ago
6 0

Answer:

1.060

Step-by-step explanation:

I added 1 tenth to the answer.I'm sorry if the answer if wrong. math isnt my best just trying to help

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Please help. Click to view picture. Algebra question. HELP ME PLEASE ASAP
Ugo [173]
Second answer if it still helps
4 0
3 years ago
suppose a population of 200 crickets double in size every 4 months. How many crickets will there be after 2 years?
tangare [24]
Well 2 years is 24 months. 24 divided by 4 is 6. 200 multiplied by 6 would equal 1200.

The total population of crickets after two years would be 1200.
4 0
3 years ago
What value of x is in the solution set of 9(2x + 1) < 9x – 18?
fredd [130]
To solve these kinds of problems, it is necessary to isolate x:

9(2x + 1) <span>< 9x - 18

Distribute 9:
18x + 9 </span><span>< 9x - 18

Subtracting 9 from both sides of the equation:
18x + 9 - 9 </span><span>< 9x - 18 - 9
18x </span><span>< 9x - 27

Subtracting 9x from both sides of the equation:
18x - 9x </span><span>< 9x - 27 - 9x
9x </span><span>< -27

x </span><span>< -3

Therefore, values of x </span><span>< -3 will satisfy the given equation.</span>
7 0
3 years ago
(8.88×10^4) + (7.48×10^4)
podryga [215]
1.636x10^5 after adding or 163600 depending on the form wanted
4 0
3 years ago
A pitcher holds 3/4 gallons of kool-aid. Martin wants to pour equal amounts of kool- aid into 6 smaller cotainers. How much kool
statuscvo [17]

Answer:

\dfrac{1}{8}\ gallons

Step-by-step explanation:

Amount of kool - aid that the pitcher can hold = \frac{3}4 gallons

There are 6 smaller containers in which this kool - aid is to be adjusted.

Also, the volume of the smaller containers is equal to each other i.e. the containers are identical to each other in terms of volume.

To find:

The amount of kool - aid that each container can hold?

Solution:

Volume of all the smaller containers combined = Volume of the kool - aid available

Let the volume of one smaller container = V

V + V + V + V + V + V = \dfrac{3}{4}\ gallons

\Rightarrow 6V = \dfrac{3}{4}\ gallons\\\Rightarrow V = \dfrac{3}{4\times 6 }\ gallons\\\Rightarrow V=\bold{\dfrac{1}{8}\ gallons}

\frac{1}{8}\ gallons of kool - aid is the amount that each smaller can hold.

8 0
3 years ago
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