Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
I would guess 40, I could be wrong.
Step-by-step explanation:
70-30=40. So it would be 40 units away from eachother.
Is there another part of this?
5/9* 32
= (5*32)/9
= 160/9
= (153+ 7)/9
= 153/9+ 7/9
= 17+ 7/9
= 17 7/9
The final answer is 17 7/9~
