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raketka [301]
3 years ago
14

Desert animals, such as the kangaroo rat, need to conserve water in their bodies. What makes this mechanisms is an efficient way

of conserving water?
Biology
1 answer:
Otrada [13]3 years ago
4 0
It is important to note that such animals living in desert conditions do not waste water by sweating to control body temperature. They mostly try burrowing during the day time to avoid getting dehydrated. Their urine is highly concentrated and it is mostly in the form of uric acid. These means help the desert animals to survive in such harsh conditions.
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Is this mRNA or rna need help please need the answer in a hurry
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Why does only 10% move to the next trophic level?
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The amount of energy at each trophic level decreases as it moves through an ecosystem. As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.
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3 years ago
The count in a bacteria culture was 100 after 20 minutes and 2000 after 40 minutes. Assuming the count grows exponentially, What
Afina-wow [57]

Answer:

Explanation:

Let X be the number of bacteria at time t, and Xo be the initial number of bacteria

Bacteria grows exponentially, the exponential growth model is thus:

X = Xo e^{kt}

[<em>e</em> is the exponential sign]

k is the growth constant = growth rate

At t = 20 minutes, X = 100

At t = 40 minutes, X = 2000

Substituting that into the formula

(i) ...    100 = Xo e^{k20}

(ii) ...    2000 = Xoe^{k40}

<em>Divide (ii) by (i)</em>

\frac{2000}{100} = \frac{Xoe^{40k} } {Xoe^{20k}}

20 = e^{40k-20k} = e^{20k}

<em>[Xo cancels Xo. Division of values raised to a power is done by subtracting their powers]</em>

<em>Take the natural log of both sides</em>

㏑20 = 20k

<em>[taking the ㏑ cancels the exponential]</em>

k = \frac{ln20}{20}

<em>We can now substitute k to solve one of the equations</em>

<em>substituting k in (ii)</em>: 2000 = Xo e\frac{ln 20}{20}.^{40}

2000 = Xo e^{0.15*40}

2000 = Xo e^{6}

<em>Making Xo the subject of the formula</em>

Xo = \frac{2000}{e^{6} }

Xo is approximately 5 cells.

THE DOUBLING TIME

The doubling time is the time it takes for the population to double, so 5 cells become 10 cells

Since Xo = 5

Given that X = Xo e^{kt}

When X=10,

10 = 5 e^{0.15t}

<em>solving for t:</em>

e^{0.15t} = \frac{10}{5}

Take ln of both sides

0.15t = ln 2

t =\frac{ln2}{0.15}

t =4.62 minutes

POPULATION AFTER 65 MINUTES

X = 5 e^{0.15*65}

X = 85770

WHEN WILL THE POPULATION REACH 12000

12000 = 5 e^{0.15t}

e^{0.15t} =240

take ln of both sides

0.15t = ln 2400

t = 51.89 minutes (approximately 52 minutes)

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Which of the following events could cause pyruvate and lactate to accumulate in the blood of individuals with PDCD?
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Mutation causes a defect in one of the three enzyme that processes pyruvate
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What is one function of the organ system shown below in the picture?
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The main function of the lungs is the process of gas exchange called respiration (or breathing). In respiration, oxygen from incoming air enters the blood, and carbon dioxide, a waste gas from the metabolism, leaves the blood. A reduced lung function means that the ability of lungs to exchange gases is reduced.
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3 years ago
Read 2 more answers
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