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Setler79 [48]
3 years ago
13

What is the solution to this system of equations? Y= 2x - 3.5 x - 2y = -14

Mathematics
2 answers:
Rudiy273 years ago
8 0

Answer:

x = 7, y = 10.5.

Step-by-step explanation:

y = 2x - 3.5

-2y = -x - 14

Multiply the first equation by 2:

2y = 4x - 7  

Now add this equation  to the second one:

0 = 3x - 21

3x = 21

x = 7.

Now substitute x = 7 in the first equation to fund the value of y:

y = 2(7) - 3.5

y = 10.5.

goldfiish [28.3K]3 years ago
6 0

Answer:

x=7

y=10.5


Step-by-step explanation:

1. You can apply the method of substitution, as you can see below:

- Substitute y=2x-3.5 into the other equation and solve fo x:

x-2(2x-3.5)=-14\\x-4x+7=-14\\x=7

- Substitute the value of x obtain into the first equation, then the value of y is:

y=2(7)-3.5\\y=10.5


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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

5 0
2 years ago
The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
Scrat [10]

Just did a specific one of these; let's do the general case.


The point nearest the origin is (a,b).


The line from the origin through the point is


bx - ay = 0


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ax + by = a^2 + b^2


ax + by -( a^2 + b^2) = 0


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3 years ago
Which is the simplified form of the expression?
Anon25 [30]

Given:

Consider the given expression is:

10n-\dfrac{1}{3}(9n-12)

To find:

The simplified form of the given expression.

Solution:

We have,

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Using distributive property, it can be written as:

=10n-\dfrac{1}{3}(9n)-\dfrac{1}{3}(-12)

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4 0
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What is the volume of a cylinder with a height of 4xy^4 and a radius of 2x? (The formula fo
OLga [1]

Answer:

volume: \sf 16\pi x^3y^4

given:

  • height: \sf 4xy^4
  • radius: \sf 2x

<u>cylinder volume</u>:

\hookrightarrow \sf \pi r^2h

\hookrightarrow  \sf \pi (2x)^2(4xy^4)

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3 0
2 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

8 0
3 years ago
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