1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alecsey [184]
2 years ago
8

Which of the following pairs of angles are supplementary? Select all that apply.

Mathematics
1 answer:
4vir4ik [10]2 years ago
4 0
Supplementary angles mean they equal 180 degrees which means any two angles that equal a line. so that would be:
<1 and <3
<1 and <4
<2 and <3
and <2 and <4

as all of these angles (in their respective pairs) create a single line which is equivalent to 180 degrees
You might be interested in
Which is the last operation performed when evaluating (8 minus 2 x) squared + 4 for x = 3?
kompoz [17]

Answer:

addition

Step-by-step explanation:

The given expression is (8-2x)^2+4

We want to determine the last operation performed when evaluating this expression for x=3.

We substitute to get:

(8-2*3)^2+4

Multiply within the parenthesis to get:

(8-6)^2+4

Subtract to get:

2^2+4

Evaluate the exponent to get:

4+4

Add to obtain:

8

Hence the final operation is addition

4 0
3 years ago
Read 2 more answers
12
Tamiku [17]

Answer:

30%. Based on the given conditions, formulate: 12/40 Cross out the common factor: 3/10 Multiply a number.

Step-by-step explanation:

5 0
2 years ago
If m&lt;ECD is six less than five times m&lt;BCE. and m&lt;BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

 of angle ECD

∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

  angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

3 0
3 years ago
Read 2 more answers
A series of tile patterns is shown below. Consider the function that represents the number of white tiles in each figure. Figure
mr_godi [17]
No one can answer this there is no picture for me or anyone else to look at
7 0
3 years ago
What is -1/8×5×2/3=<br>please help me
Serga [27]
-10/24 is the answer. 
6 0
3 years ago
Other questions:
  • The speed of light in a vacuum is 299,792,458 meters per second. Which number written in scientific notation is the best approxi
    5·2 answers
  • John has a bag of marbles that contains 12 red marbles, 20 green marbles, and 17 blue marbles
    13·1 answer
  • 1.The experimental probability that an SUV will pass by Matthew's store is 0.4. If 500 cars pass by Matthew’s store, how many ca
    9·1 answer
  • You are interested in estimating the the mean weight of the local adult population of female white-tailed deer (doe). From past
    11·1 answer
  • What is the slope of the line that passes through the points (5, -11) and (-9, 17)?
    8·1 answer
  • Graph 1<br> Parallel<br> Perpendicular<br> Neither
    7·1 answer
  • What number when added to 13 gives 2?​
    11·2 answers
  • Sariyah cuts 22 yards of cloth into 8 pieces of equal length the lengths of each pieces falls between two measures
    15·1 answer
  • 1 1/5 · x/3 = 9/10<br> solve for x
    9·1 answer
  • 35. A can of popcorn is to be packed in a box for shipping as shown. The can is 18 inches tall and has a radius of 7 inches. The
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!